题目内容
In the Rt△ABC，∠ACB＝90°，AB＋BC＋CA＝2＋，midline for hypotenuse（斜边）is 1，then AC·BC＝__________．
1
In Fig.2,In the Rt△ABC，∠ACB=900，∠A=300，CD is the bisector to
∠ACB，MD is the perpendicular to BA and MD through the midpoint of segment AB，thrn ∠CDM= .(英语小词典：bisector：平分线；perpendicular：垂线；midpoint：中点)
，midline for hypotenuse（斜边）is 1，then AC·BC＝__________．
，midline for hypotenuse（斜边）is 1，then AC·BC＝__________．
16、In Fig．，In the Rt△ABC，∠ACB=90°，∠A=30°，CD is the bisector to∠ACB，MD is the perpendicular to BA and MD through the midpoint of segment AB，then∠CDM=
In Fig，In the Rt△ABC，∠ACB=90°，∠A=30°，CD is the bisector to∠ACB，MD is the perpendicular to BA and MD through the midpoint of segment AB，then∠CDM=________．
nt AB，thrn ∠CDM= .(英语小词典：bisector：平分线；perpendicular：垂线；midpoint：中点)