题目内容
计算:(2a |
a-1 |
a |
a+1 |
a2-1 |
a |
分析:首先把括号里的式子进行通分,然后进行约分化简.
解答:解:原式=
•
=
•
=
=a+3.
2a(a+1)(a-1) |
a2-1 |
a2-1 |
a |
=
a2+3a |
a2-1 |
a2-1 |
a |
=
a2+3a |
a |
=a+3.
点评:分式的四则运算是整式四则运算的进一步发展,在计算时,首先要弄清楚运算顺序,先去括号,再进行分式的乘除.
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