题目内容
计算:(
-
)•
2a |
a-1 |
a |
a+1 |
a2-1 |
a |
原式=
•
=
•
=
=a+3.
2a(a+1)(a-1) |
a2-1 |
a2-1 |
a |
=
a2+3a |
a2-1 |
a2-1 |
a |
=
a2+3a |
a |
=a+3.
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题目内容
2a |
a-1 |
a |
a+1 |
a2-1 |
a |
2a(a+1)(a-1) |
a2-1 |
a2-1 |
a |
a2+3a |
a2-1 |
a2-1 |
a |
a2+3a |
a |