题目内容
如图,点P是⊙O直径AB的延长线上一点,PC切⊙O于点C,已知OB=3,PB=2.则PC等于( )
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A.2 | B.3 | C.4 | D.5 |
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∵PC、PB分别为⊙O的切线和割线,
∴PC2=PB•PA,
∵OB=3,PB=2,
∴PA=8,
∴PC2=PB•PA=2×8=16,
∴PC=4.
故选C.
∴PC2=PB•PA,
∵OB=3,PB=2,
∴PA=8,
∴PC2=PB•PA=2×8=16,
∴PC=4.
故选C.
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