题目内容
已知关于
的方程
有两个不相等的实数根
、
,且
.
(1)求证:
;
(2)试用
的代数式表示
;
(3)当
时,求
的值.





(1)求证:

(2)试用


(3)当


(1)见解析(2)
或
(3)1


⑴证明:∵关于
的方程
有两个不相等的实数根,
∴△=
,∴
.
又
,∴
.
⑵
或
(3)当
时,k=1.当
时,k不存在.所求的k的值为1
(1)方程有两个不相等的实数根,则△>0,建立关于n,k的不等式,结合不等式的性质,证出结论;
(2)根据根与系数的关系,把x1+x2=k代入已知条件(2x1+x2)2-8(2x1+x2)+15=0,即可用k的代数式表示x1;
(3)首先由(1)知n<-
k2,又n=-3,求出k的范围.再把(2)中求得的关系式代入原方程,即可求出k的值.


∴△=


又


⑵


(3)当


(1)方程有两个不相等的实数根,则△>0,建立关于n,k的不等式,结合不等式的性质,证出结论;
(2)根据根与系数的关系,把x1+x2=k代入已知条件(2x1+x2)2-8(2x1+x2)+15=0,即可用k的代数式表示x1;
(3)首先由(1)知n<-


练习册系列答案
相关题目