题目内容
(7分)如图,南京绿博园中有一条人工河,河的两岸PQ、MN互相平行,河岸PQ上有一排间隔为50米的彩灯柱C、D、E、……,某人在河岸MN的A处测得∠DAN=21º,然后沿河岸走了175米到达B处,测得∠CBN=45º,求这条河的宽度.(参考数据:,)
作AS⊥PQ,CT⊥MN,垂足分别为S,T.
由题意知,四边形ATCS为矩形,
所以AS=CT,SC=AT.
设这条河的宽度为x米.
在Rt△ADS中,因为,
所以. ······················································(2分)
在Rt△BCT中,因为,
所以. ······················································(3分)
因为SD+DC =AB+BT,所以,···············································(6分)
解得,即这条河的宽度为75米. ······················································(7分)
(其它方法相应给分)
由题意知,四边形ATCS为矩形,
所以AS=CT,SC=AT.
设这条河的宽度为x米.
在Rt△ADS中,因为,
所以. ······················································(2分)
在Rt△BCT中,因为,
所以. ······················································(3分)
因为SD+DC =AB+BT,所以,···············································(6分)
解得,即这条河的宽度为75米. ······················································(7分)
(其它方法相应给分)
略
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