题目内容
(1)先化简,再求值:(
-
)•
,其中a=
+1(精确到0.01);
(2)当b≠0时,比较
与1的大小.
3a |
a+1 |
a2-1 |
a+1 |
a2-1 |
a |
7 |
(2)当b≠0时,比较
b+1 |
(1)原式=
•
-
•
=3(a-1)-
当a=
+1时,
原式=3(
+1)-
=3
+3-
=3
+3-
=3
+3-
=3
+3-
-
=
-
=
≈
=2.02;
(2)因为b+1<0时二次根式无意义,所以:
①0<b+1<1时,
<1;
②b+1=1时,
=1;
③b+1>1时,
>1.
3a |
a+1 |
(a-1)(a+1) |
a |
(a-1)(a+1) |
a+1 |
(a-1)(a+1) |
a |
(a+1)(a-1)2 |
a |
当a=
7 |
原式=3(
7 |
(
| ||||
|
=3
7 |
7(
| ||
|
=3
7 |
7(
| ||||
6 |
=3
7 |
7(5+
| ||
6 |
=3
7 |
35 |
6 |
7
| ||
6 |
=
11
| ||
6 |
17 |
6 |
=
11
| ||
6 |
≈
11×2.646-17 |
6 |
=2.02;
(2)因为b+1<0时二次根式无意义,所以:
①0<b+1<1时,
b+1 |
②b+1=1时,
b+1 |
③b+1>1时,
b+1 |
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