题目内容
计算
+
(1+
)+
(1+
)(1+
)+
(1+
)(1+
)(1+
)-(1+
)(1+
)(1+
)(1+
).
1 |
a |
1 |
b |
1 |
a |
1 |
c |
1 |
a |
1 |
b |
1 |
d |
1 |
a |
1 |
b |
1 |
c |
1 |
a |
1 |
b |
1 |
c |
1 |
d |
分析:原式后两项提取公因式,化简后后两项再提取公因式,依此类推即可得到结果.
解答:解:原式=
+
(1+
)+
(1+
)(1+
)+(1+
)(1+
)(1+
)(
-1-
)
=
+
(1+
)+(1+
)(1+
)(
-1+
)
=
+(1+
)(
-1-
)
=
-1-
=-1.
1 |
a |
1 |
b |
1 |
a |
1 |
c |
1 |
a |
1 |
b |
1 |
a |
1 |
b |
1 |
c |
1 |
d |
1 |
d |
=
1 |
a |
1 |
b |
1 |
a |
1 |
a |
1 |
b |
1 |
c |
1 |
c |
=
1 |
a |
1 |
a |
1 |
b |
1 |
b |
=
1 |
a |
1 |
a |
=-1.
点评:此题考查了分式的混合运算,分式的加减运算关键是通分,通分的关键是找最简公分母;分式的乘除运算关键是约分,约分的关键是找公因式.
练习册系列答案
相关题目
计算
÷
-
+1的正确结果为( )
a2-2a+1 |
a2-1 |
a2-a |
a+1 |
1 |
a |
A、
| ||
B、1 | ||
C、2 | ||
D、-
|