题目内容
化简:(每小题3分)
(1)
(2)
(1)
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(2)
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(1)
; (2)
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(1)没有括号,直接合并同类项即可;
(2)先去括号,再合并同类项;
(3)按照整式的加减运算顺序,有括号的先算括号里面的.
解:(1)原式=(5-9)m+(-7+5)n-(8+1)p
=
;
(2)原式=3(-3a2-2a)-[a2+5a-4a2+1-3a]
=-9a2-6a+3a2-2a-1
=
.
(2)先去括号,再合并同类项;
(3)按照整式的加减运算顺序,有括号的先算括号里面的.
解:(1)原式=(5-9)m+(-7+5)n-(8+1)p
=

(2)原式=3(-3a2-2a)-[a2+5a-4a2+1-3a]
=-9a2-6a+3a2-2a-1
=
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