题目内容
如图,AB∥CD,∠B=28°,∠D=32°,则∠E=______.
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如图,过点E作EF∥AB,
∵AB∥CD,
∴AB∥EF∥CD,
∴∠1=∠B=28°,
∠2=∠D=32°,
∴∠E=∠1+∠2=28°+32°=60°.
故答案为:60°.
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∵AB∥CD,
∴AB∥EF∥CD,
∴∠1=∠B=28°,
∠2=∠D=32°,
∴∠E=∠1+∠2=28°+32°=60°.
故答案为:60°.
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