题目内容
分解因式:
(1)x2-2x+1=________;
(2)4y2+12y+9=________.
(1)(x-1)2 (2)(2y+3)2
-(2x2)4=________.
化简求值:
(a-b)2+b(a-b),其中a=2,b=-3.
下列从左到右的变形,属于正确的分解因式的是
A.
(y+2)(y-2)=y2-4
B.
a2+2a+1=a(a+2)+1
C.
b2+6b+9=(b+3)2
D.
x2-5x-6=(x-1)(x+6)
计算:
(1)(x-1)(x+1)=________;
(2)(y+4)(y-4)=________.
代数式x4-16,x2-4x+4,x2-4的公因式是
x+2
x-2
x2-4
x-4
(1)6xy2-9x2y-y3;
(2)(2a-b)2+8ab.
分解因式:ab2-4a=________.
[(-ab)3+(a2b)2]÷(-ab)2=________.