题目内容

【题目】如图,BCACBC=8AC=6AB=10,则点 C 到线段 AB 的距离是_____

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【答案】4.8

【解析】如图,过点CCD⊥AB于点D,

∵BC⊥AC,

SABC=AC·BC=AB·CD

∵AC=6BC=8AB=10

CD解得CD=4.8

即点CAB的距离为4.8.

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