题目内容
(2008•达州)(1)计算:(-1)2008+![](http://thumb.zyjl.cn/pic6/res/czsx/web/STSource/20131021231547804891936/SYS201310212315478048919003_ST/0.png)
(2)先将
![](http://thumb.zyjl.cn/pic6/res/czsx/web/STSource/20131021231547804891936/SYS201310212315478048919003_ST/1.png)
【答案】分析:这道求代数式值的题目,不应考虑把x的值直接代入,通常做法是先把代数式化简,然后再代入求值.分式的四则运算是整式四则运算的进一步发展,是有理式恒等变形的重要内容之一.在计算时,首先要弄清楚运算顺序,先去括号,再进行分式的乘除.
解答:解:
(1)原式=1+
-![](http://thumb.zyjl.cn/pic6/res/czsx/web/STSource/20131021231547804891936/SYS201310212315478048919003_DA/1.png)
=1+
-![](http://thumb.zyjl.cn/pic6/res/czsx/web/STSource/20131021231547804891936/SYS201310212315478048919003_DA/3.png)
=1;
(2)原式=![](http://thumb.zyjl.cn/pic6/res/czsx/web/STSource/20131021231547804891936/SYS201310212315478048919003_DA/4.png)
=![](http://thumb.zyjl.cn/pic6/res/czsx/web/STSource/20131021231547804891936/SYS201310212315478048919003_DA/5.png)
=x,
取x=10,则原式=10.
点评:本题除考查了分式的混合运算外,还考查了特殊三角函数的值.
解答:解:
(1)原式=1+
![](http://thumb.zyjl.cn/pic6/res/czsx/web/STSource/20131021231547804891936/SYS201310212315478048919003_DA/0.png)
![](http://thumb.zyjl.cn/pic6/res/czsx/web/STSource/20131021231547804891936/SYS201310212315478048919003_DA/1.png)
=1+
![](http://thumb.zyjl.cn/pic6/res/czsx/web/STSource/20131021231547804891936/SYS201310212315478048919003_DA/2.png)
![](http://thumb.zyjl.cn/pic6/res/czsx/web/STSource/20131021231547804891936/SYS201310212315478048919003_DA/3.png)
=1;
(2)原式=
![](http://thumb.zyjl.cn/pic6/res/czsx/web/STSource/20131021231547804891936/SYS201310212315478048919003_DA/4.png)
=
![](http://thumb.zyjl.cn/pic6/res/czsx/web/STSource/20131021231547804891936/SYS201310212315478048919003_DA/5.png)
=x,
取x=10,则原式=10.
点评:本题除考查了分式的混合运算外,还考查了特殊三角函数的值.
![](http://thumb.zyjl.cn/images/loading.gif)
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