题目内容
如图,∠AOC=∠BOD=90°,且∠AOB=155°,则∠COD=______.
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根据∠AOC=∠BOD=90°,且∠AOB=155°,
∴∠BOC=∠AOB-∠AOC=155°-90°=65°,
∴∠COD=∠BOD-∠BOC=90°-65°=25°.
故答案为:25°.
∴∠BOC=∠AOB-∠AOC=155°-90°=65°,
∴∠COD=∠BOD-∠BOC=90°-65°=25°.
故答案为:25°.
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