题目内容
已知
=
,求
的值.
x |
x2-1+1 |
1 |
3 |
x2 |
x2+x+1 |
∵
=
=
,
∴x=3,
则原式=
=
.
x |
x2-1+1 |
1 |
x |
1 |
3 |
∴x=3,
则原式=
9 |
9+3+1 |
9 |
13 |
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题目内容
x |
x2-1+1 |
1 |
3 |
x2 |
x2+x+1 |
x |
x2-1+1 |
1 |
x |
1 |
3 |
9 |
9+3+1 |
9 |
13 |