题目内容
先化简,再求值:(
)+
,其中x=(-1)2012+tan60°.
3x+2 |
x2-1 |
x |
x+1 |
原式=
+
=
=
=
,
∵x=(-1)2012+tan60°=1+
,
∴原式=
=
=
=
=
.
3x+2 |
(x+1)(x-1) |
x(x-1) |
(x+1)(x-1) |
=
3x+2+x2-x |
(x+1)(x-1) |
=
2x+2+x2 |
(x+1)(x-1) |
=
(x+1)2+1 |
(x+1)(x-1) |
∵x=(-1)2012+tan60°=1+
3 |
∴原式=
(1+
| ||||
(1+
|
=
(2+
| ||||
(2+
|
=
4+3+4
| ||
2
|
=
4(2+
| ||
2
|
=
4
| ||
3 |
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