题目内容

先化简,再求值:(
3x+2
x2-1
)+
x
x+1
,其中x=(-1)2012+tan60°.
原式=
3x+2
(x+1)(x-1)
+
x(x-1)
(x+1)(x-1)

=
3x+2+x2-x
(x+1)(x-1)

=
2x+2+x2
(x+1)(x-1)

=
(x+1)2+1
(x+1)(x-1)

∵x=(-1)2012+tan60°=1+
3

∴原式=
(1+
3
+1)2+1
(1+
3
+1)(1+
3
-1)

=
(2+
3
)
2
+1
(2+
3
3

=
4+3+4
3
+1
2
3
+3

=
4(2+
3
)
2
3
+3

=
4
3
3
练习册系列答案
相关题目

违法和不良信息举报电话:027-86699610 举报邮箱:58377363@163.com

精英家教网