题目内容
计算:
(1)
+
(2)
-
÷
.
(1)
a |
a-b |
b |
b-a |
(2)
1 |
x+2 |
x2+2x+1 |
x+2 |
x2-1 |
x-1 |
(1)原式=
-
=
=1;
(2)原式=
-
•
=
-
=-
.
a |
a-b |
b |
a-b |
=
a-b |
a-b |
=1;
(2)原式=
1 |
x+2 |
(x+1)2 |
x+2 |
1 |
x+1 |
=
1 |
x+2 |
x+1 |
x+2 |
=-
x |
x+2 |
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