ÌâÄ¿ÄÚÈÝ
£¨11·Ö£©¹¹½¨ÖªÊ¶ÍøÂçÊÇÒ»ÖÖÖØÒªµÄѧϰ·½·¨¡£Í¼ÎªÄ³Ð£»¯Ñ§Ñ§Ï°Ð¡×éµÄСÑôͬѧ»æÖƵÄÌúµÄ»¯Ñ§ÐÔÖÊÍøÂçʾÒâͼ¡£Çë·ÖÎö»Ø´ðÏÂÁÐÎÊÌ⣺
(1)·´Ó¦¢ÙÖпÉÓà ¡ø (Ìѧʽ)×÷»¹Ô¼Á£»
¢Æд³ö¸ß¯Öз¢ÉúµÄ·´Ó¦¢ÙµÄ»¯Ñ§·½³Ì
ʽ£º ¡ø £»
д³ö·´Ó¦¢ÛµÄ»¯Ñ§·½³Ìʽ ¡ø £»
¢Ç·´Ó¦¢Úµ¼ÖÂÿÄêÓдóÁ¿µÄ¸ÖÌúÐâÊ´£¬Îª×èÖ¹¸Ã·´Ó¦µÄ·¢Éú£¬ÈËÃdz£²ÉÓÃÔÚ¸ÖÌú±íÃæÍ¿Ë¢ÓÍÆá»ò¶ÆÉÏÆäËü½ðÊôµÈ·½·¨¡£ÕâÁ½ÖÖ·½·¨µÄ¹²Í¬ÔÀíÊÇ×èÖ¹¸ÖÌú
Óë ¡ø ½Ó´¥£»
¢È¸Ã»¯Ñ§Ñ§Ï°Ð¡×éΪÁË·ÖÎöÉúÌúÖÐÌúµÄº¬Á¿£¬½øÐÐÁËÈçÏÂʵÑéÑо¿£ºÈ¡12gÉúÌúÓë10%µÄÑÎËá·´Ó¦£¬²¢»æÖÆÁ˼ÓÈëÑÎËáÖÊÁ¿Óë·Å³öÆøÌåÖÊÁ¿µÄ¹Øϵͼ£¨¼ûÓÒÏÂͼ£©¡££¨ËµÃ÷£ºÉúÌúÖÐÔÓÖʲ»ÈÜÓÚË®£¬²»ÓëÑÎËá¡¢ÁòËáÍÈÜÒº·´Ó¦¡££©
¢ÙÌúÍêÈ«·´Ó¦ÓÃÈ¥ÑÎËáµÄÖÊÁ¿Îª ¡ø g¡£
¢ÚÉúÌúÖÐÌúµÄÖÊÁ¿·ÖÊýΪ¶àÉÙ£¿£¨Ð´³ö¼ÆËã¹ý³Ì£¬½á¹û±£Áôµ½Ð¡Êýµãºóһ룩
¡ø
£¨5£©Ä³Í¬Ñ§ÁгöÁËÈçϼÆËãʽ£º
ÉúÌúÓëÑÎËá¸ÕºÃ·´Ó¦ÍêȫʱËùµÃÈÜÒºÖÊÁ¿= (146+12-a)g
СÃ÷¶Ô¸Ã¼ÆËãʽÌá³öÁËÖÊÒÉ£¬ÇëÖ¸³öÆäÖеĴíÎó ¡ø
¡£
£¨6£©Ð¡»ªÁíÉè¼ÆÁËÒ»¸öʵÑé·½°¸£ºÓÃ12gÉúÌú·ÛÓë20%µÄÁòËáÍÈÜÒº·´Ó¦À´·ÖÎöÉúÌúÖÐÌúµÄº¬Á¿¡£ÇëÄ㻳ö¼ÓÈëÁòËáÍÈÜÒºÖÊÁ¿Óë¹ÌÌåÖÊÁ¿±ä»¯¹ØϵµÄÇúÏß¡£
(1)·´Ó¦¢ÙÖпÉÓà ¡ø (Ìѧʽ)×÷»¹Ô¼Á£»
¢Æд³ö¸ß¯Öз¢ÉúµÄ·´Ó¦¢ÙµÄ»¯Ñ§·½³Ì
ʽ£º ¡ø £»
д³ö·´Ó¦¢ÛµÄ»¯Ñ§·½³Ìʽ ¡ø £»
¢Ç·´Ó¦¢Úµ¼ÖÂÿÄêÓдóÁ¿µÄ¸ÖÌúÐâÊ´£¬Îª×èÖ¹¸Ã·´Ó¦µÄ·¢Éú£¬ÈËÃdz£²ÉÓÃÔÚ¸ÖÌú±íÃæÍ¿Ë¢ÓÍÆá»ò¶ÆÉÏÆäËü½ðÊôµÈ·½·¨¡£ÕâÁ½ÖÖ·½·¨µÄ¹²Í¬ÔÀíÊÇ×èÖ¹¸ÖÌú
Óë ¡ø ½Ó´¥£»
¢È¸Ã»¯Ñ§Ñ§Ï°Ð¡×éΪÁË·ÖÎöÉúÌúÖÐÌúµÄº¬Á¿£¬½øÐÐÁËÈçÏÂʵÑéÑо¿£ºÈ¡12gÉúÌúÓë10%µÄÑÎËá·´Ó¦£¬²¢»æÖÆÁ˼ÓÈëÑÎËáÖÊÁ¿Óë·Å³öÆøÌåÖÊÁ¿µÄ¹Øϵͼ£¨¼ûÓÒÏÂͼ£©¡££¨ËµÃ÷£ºÉúÌúÖÐÔÓÖʲ»ÈÜÓÚË®£¬²»ÓëÑÎËá¡¢ÁòËáÍÈÜÒº·´Ó¦¡££©
¢ÙÌúÍêÈ«·´Ó¦ÓÃÈ¥ÑÎËáµÄÖÊÁ¿Îª ¡ø g¡£
¢ÚÉúÌúÖÐÌúµÄÖÊÁ¿·ÖÊýΪ¶àÉÙ£¿£¨Ð´³ö¼ÆËã¹ý³Ì£¬½á¹û±£Áôµ½Ð¡Êýµãºóһ룩
¡ø
£¨5£©Ä³Í¬Ñ§ÁгöÁËÈçϼÆËãʽ£º
ÉúÌúÓëÑÎËá¸ÕºÃ·´Ó¦ÍêȫʱËùµÃÈÜÒºÖÊÁ¿= (146+12-a)g
СÃ÷¶Ô¸Ã¼ÆËãʽÌá³öÁËÖÊÒÉ£¬ÇëÖ¸³öÆäÖеĴíÎó ¡ø
¡£
£¨6£©Ð¡»ªÁíÉè¼ÆÁËÒ»¸öʵÑé·½°¸£ºÓÃ12gÉúÌú·ÛÓë20%µÄÁòËáÍÈÜÒº·´Ó¦À´·ÖÎöÉúÌúÖÐÌúµÄº¬Á¿¡£ÇëÄ㻳ö¼ÓÈëÁòËáÍÈÜÒºÖÊÁ¿Óë¹ÌÌåÖÊÁ¿±ä»¯¹ØϵµÄÇúÏß¡£
(1)C»òH2»òCO£¨0.5·Ö£©
£¨2£© ¸ßÎÂ
Fe2O3+3CO====2Fe+3CO2
Fe+CuSO4==FeSO4+Cu£¨»òFe+CuCl2==FeCl2+Cu»ò Fe+Cu£¨NO3£©2==Fe£¨NO3£©2+Cu £©
(3)¿ÕÆøºÍË®£¨»òÑõÆøºÍË®£©
£¨4£©¢Ù146£¨0.5·Ö£©
¢Ú£¨¹²4·Ö
½â£ºÉèÓëÑÎËá·´Ó¦µÄÌúµÄµÄÖÊÁ¿Îªx¡£ 0.5·Ö
Fe + 2HCl £½ FeCl2 + H2¡ü(1·Ö)
56 73
x 146 g¡Á10%="14.6" g
x =" 11.2g" 0.5·Ö
ÉúÌúÖÐÌúµÄÖÊÁ¿·ÖÊýΪ=£¨11.2g¡Â12g£©¡Á100% = 93.3% 1·Ö
´ð£ºÉúÌúÖÐÌúµÄÖÊÁ¿·ÖÊýΪ93.3%¡£
£¨5£©ÈÜÒºÖÊÁ¿²»°üÀ¨ÇâÆøÖÊÁ¿ºÍÊ£ÓàÔÓÖʵÄÖÊÁ¿£¬ËùÒÔ»¹Òª¼õÈ¥ÔÓÖʵÄÖÊÁ¿
£¨6£©×¥×¡Æðµã¡¢Õ۵㼰ÇúÏß×ßÊƸø·Ö£¬²»ÐèÒª±ê×¢ÕâЩµã£¬×¥×¡Æðµã¡¢Õ۵㼰ÇúÏß×ßÊÆÆÀ·Ö£¬´íÒ»´¦²»¸ø·Ö£»ÇúÏßÁ½¶Î¾ùΪֱÏߣ¬Æ«²îÌ«´ó²»¸ø·Ö£»ÔÚÆðµã¡¢Õ۵㼰ÇúÏß×ßÊÆûÓдíÎóµÄÇé¿öÏ£¬»µÃ²»µ½Î»£¨ÈçÖ»»ÁËÇ°°ë²¿·Ö£¬ÇÒÕýÈ·£©µÄ¿ÉÊʵ±¿Û·Ö¡£¹²2·Ö£©
£¨2£© ¸ßÎÂ
Fe2O3+3CO====2Fe+3CO2
Fe+CuSO4==FeSO4+Cu£¨»òFe+CuCl2==FeCl2+Cu»ò Fe+Cu£¨NO3£©2==Fe£¨NO3£©2+Cu £©
(3)¿ÕÆøºÍË®£¨»òÑõÆøºÍË®£©
£¨4£©¢Ù146£¨0.5·Ö£©
¢Ú£¨¹²4·Ö
½â£ºÉèÓëÑÎËá·´Ó¦µÄÌúµÄµÄÖÊÁ¿Îªx¡£ 0.5·Ö
Fe + 2HCl £½ FeCl2 + H2¡ü(1·Ö)
56 73
x 146 g¡Á10%="14.6" g
x =" 11.2g" 0.5·Ö
ÉúÌúÖÐÌúµÄÖÊÁ¿·ÖÊýΪ=£¨11.2g¡Â12g£©¡Á100% = 93.3% 1·Ö
´ð£ºÉúÌúÖÐÌúµÄÖÊÁ¿·ÖÊýΪ93.3%¡£
£¨5£©ÈÜÒºÖÊÁ¿²»°üÀ¨ÇâÆøÖÊÁ¿ºÍÊ£ÓàÔÓÖʵÄÖÊÁ¿£¬ËùÒÔ»¹Òª¼õÈ¥ÔÓÖʵÄÖÊÁ¿
£¨6£©×¥×¡Æðµã¡¢Õ۵㼰ÇúÏß×ßÊƸø·Ö£¬²»ÐèÒª±ê×¢ÕâЩµã£¬×¥×¡Æðµã¡¢Õ۵㼰ÇúÏß×ßÊÆÆÀ·Ö£¬´íÒ»´¦²»¸ø·Ö£»ÇúÏßÁ½¶Î¾ùΪֱÏߣ¬Æ«²îÌ«´ó²»¸ø·Ö£»ÔÚÆðµã¡¢Õ۵㼰ÇúÏß×ßÊÆûÓдíÎóµÄÇé¿öÏ£¬»µÃ²»µ½Î»£¨ÈçÖ»»ÁËÇ°°ë²¿·Ö£¬ÇÒÕýÈ·£©µÄ¿ÉÊʵ±¿Û·Ö¡£¹²2·Ö£©
·ÖÎö£º£¨1£©³£ÓõĻ¹Ô¼ÁÓÐ̼¡¢Ò»Ñõ»¯Ì¼ºÍÇâÆøÈýÖÖ£»
£¨2£©¸ß¯Á¶ÌúÊÇÓÃÒ»Ñõ»¯Ì¼»¹ÔÑõ»¯Ìú£»ÌúÖû»ÍÊÇÌúºÍ͵ÄÑÎÈÜÒº·´Ó¦£»
£¨3£©ÌúÉúÐâµÄÌõ¼þÊÇÌúÓëÑõÆøºÍˮͬʱ½Ó´¥£»
£¨4£©ÓÐͼ¿ÉÖ±½Ó¿´³öÍêÈ«·´Ó¦ÏûºÄÑÎËáÈÜÒºµÄÖÊÁ¿£¬¸ù¾ÝÌúºÍÑÎËá·´Ó¦µÄ·½³Ìʽ£¬ÀûÓÃÑÎËáÈÜÖÊÖÊÁ¿¿ÉµÃµ½²Î¼Ó·´Ó¦µÄÌúµÄÖÊÁ¿£¬½ø¶øÇó³öÉúÌúÖÐÌúµÄÖÊÁ¿·ÖÊý£»
£¨5£©·´Ó¦ºóÈÜÒºÖÊÁ¿=²Î¼Ó·´Ó¦µÄ¹ÌÌåÖÊÁ¿+ÒºÌåÖÊÁ¿-³ÁµíÖÊÁ¿-ÆøÌåÖÊÁ¿£»
£¨6£©´ËͼµÄÆðµãÈÝÒ×ÕÒµ½£¬¹Ø¼üÊÇÕÒµ½¹Õµã£¬¼´ÌúºÍÁòËáÍÇ¡ºÃÍêÈ«·´Ó¦Ê±ÏûºÄµÄÁòËáÍÈÜÒºµÄÖÊÁ¿£¬ºÍÊ£Óà¹ÌÌåµÄÖÊÁ¿£®
½â£º£¨1£©¿ÉÒÔ×ö»¹Ô¼ÁÓÐC»òH2»òCO£¬ËùÒÔÔÚ¢Ù´¦¿ÉÈÎдһ¸ö£®
£¨2£©¸ß¯Á¶ÌúÊÇÒ»¸ö¸´ÔӵĹý³Ì£¬ÆäÖÐÖ÷ÒªÊÇÀûÓý¹Ì¿ºÍÑõÆø·´Ó¦Éú³ÉµÄÒ»Ñõ»¯Ì¼°ÑÌú´ÓÌú¿óʯÖл¹Ô³öÀ´£¬·½³ÌʽΪFe2O3+3CO====2Fe+3CO2ÌúºÍ͵ÄÑÎÈÜÒº·´Ó¦¿É°ÑÍÖû»³öÀ´£¬Èç·½³ÌʽÓÐFe+CuSO4¨TFeSO4+Cu»òFe+CuCl2¨TFeCl2+Cu»ò Fe+Cu£¨NO3£©2¨TFe£¨NO3£©2+Cu£®
£¨3£©ÌúÉúÐâµÄÌõ¼þÊÇÌúÓëÑõÆøºÍˮͬʱ½Ó´¥£¬ËùÒÔ·ÀÖ¹ÌúÉúÐâµÄÔÀí¾ÍÊÇʹÌú¸ô¾ø¿ÕÆøºÍË®£¨»òÑõÆøºÍË®£©£®
£¨4£©¢ÙÓÐͼ¿ÉÖªÌúÍêÈ«·´Ó¦Ê±ÏûºÄµÄÑÎËáÖÊÁ¿ÊÇ146g£®
¢Ú½â£ºÉèÓëÑÎËá·´Ó¦µÄÌúµÄÖÊÁ¿Îªx£®
Fe+2HCl=FeCl2+H2¡ü
56 73
x 146 g¡Á10%="14.6" g
½âµÃ£ºx=11.2g
ÉúÌúÖÐÌúµÄÖÊÁ¿·ÖÊýΪ£º
¡Á100%=93.3%
´ð£ºÉúÌúÖÐÌúµÄÖÊÁ¿·ÖÊýΪ93.3%£®
£¨5£©ÒòΪÈÜÒºÖÊÁ¿²»°üÀ¨ÇâÆøÖÊÁ¿ºÍÊ£ÓàÔÓÖʵÄÖÊÁ¿£¬ËùÒÔ»¹Òª¼õÈ¥ÔÓÖʵÄÖÊÁ¿£®
£¨6£©ÌúºÍÁòËáÍ»¹Î´·´Ó¦Ê±¹ÌÌå¾ÍÊÇÌúÖÊÁ¿Îª12g£¬¹ÊÆðµãÓ¦´Ó×ÝÖáÉÏ12¿ªÊ¼»Æð£»
È»ºóÕҹյ㣬¼´ÌúºÍÁòËáÍÇ¡ºÃÍêÈ«·´Ó¦Ê±ÏûºÄµÄÁòËáÍÈÜÒºÖÊÁ¿¼°¹ÌÌåÖÊÁ¿£¬
ÉèÌúºÍÁòËáÍÇ¡ºÃÍêÈ«·´Ó¦Ê±ÏûºÄÁòËáÍÈÜҺΪy£¬Éú³ÉÍΪz
Fe+CuSO4 ¨TFeSO4 +Cu
56 160 64
11.2g 20%?y z
y=160g
z=12.8g
12gÉúÌúÖÐËùº¬ÔÓÖÊΪ£º12g-11.2g=0.8g
ËùÒÔÌúºÍÁòËáÍÇ¡ºÃÍêÈ«·´Ó¦Ê±¹ÌÌåÖÊÁ¿Îª£º12.8g+0.8g=13.6g
¼´¹Õµã´¦ºá×ø±êֵΪ160£¬×Ý×ø±êֵΪ13.6£¬È»ºó°Ñ¹ÕµãºÍÆðµãÁ¬ÆðÀ´£¬²¢ÇÒÔÚ¹Õµãºó»Ò»ÌõƽÐÐÓÚxÖáµÄÖ±Ïߣ¬¾ÍµÃµ½ÁËËùÒªµÄÇúÏßͼ£®
¹Ê´ð°¸Îª£º£¨1£©CO£»£¨2£©Fe2O3+3CO2Fe+3CO2£¬Fe+CuSO4¨TFeSO4+Cu£»
£¨3£©¿ÕÆøºÍË®£»
£¨4£©¢Ù146£¬¢Ú93.3%£»
£¨5£©ÈÜÒºÖÊÁ¿²»°üÀ¨Ê£ÓàÔÓÖʵÄÖÊÁ¿£¬ËùÒÔ»¹Òª¼õÈ¥ÔÓÖʵÄÖÊÁ¿£»
£¨6£©
´ËÌâÊÇ×ÛºÏÐÔ½ÏÇ¿µÄÌâÄ¿£¬°üÀ¨µÄÎÊÌâ½Ï¶à£¬Éæ¼°µÄ֪ʶÃæºÜ¹ã£¬ÊôÓÚÄѶȽϴóµÄÌâÄ¿£®
£¨2£©¸ß¯Á¶ÌúÊÇÓÃÒ»Ñõ»¯Ì¼»¹ÔÑõ»¯Ìú£»ÌúÖû»ÍÊÇÌúºÍ͵ÄÑÎÈÜÒº·´Ó¦£»
£¨3£©ÌúÉúÐâµÄÌõ¼þÊÇÌúÓëÑõÆøºÍˮͬʱ½Ó´¥£»
£¨4£©ÓÐͼ¿ÉÖ±½Ó¿´³öÍêÈ«·´Ó¦ÏûºÄÑÎËáÈÜÒºµÄÖÊÁ¿£¬¸ù¾ÝÌúºÍÑÎËá·´Ó¦µÄ·½³Ìʽ£¬ÀûÓÃÑÎËáÈÜÖÊÖÊÁ¿¿ÉµÃµ½²Î¼Ó·´Ó¦µÄÌúµÄÖÊÁ¿£¬½ø¶øÇó³öÉúÌúÖÐÌúµÄÖÊÁ¿·ÖÊý£»
£¨5£©·´Ó¦ºóÈÜÒºÖÊÁ¿=²Î¼Ó·´Ó¦µÄ¹ÌÌåÖÊÁ¿+ÒºÌåÖÊÁ¿-³ÁµíÖÊÁ¿-ÆøÌåÖÊÁ¿£»
£¨6£©´ËͼµÄÆðµãÈÝÒ×ÕÒµ½£¬¹Ø¼üÊÇÕÒµ½¹Õµã£¬¼´ÌúºÍÁòËáÍÇ¡ºÃÍêÈ«·´Ó¦Ê±ÏûºÄµÄÁòËáÍÈÜÒºµÄÖÊÁ¿£¬ºÍÊ£Óà¹ÌÌåµÄÖÊÁ¿£®
½â£º£¨1£©¿ÉÒÔ×ö»¹Ô¼ÁÓÐC»òH2»òCO£¬ËùÒÔÔÚ¢Ù´¦¿ÉÈÎдһ¸ö£®
£¨2£©¸ß¯Á¶ÌúÊÇÒ»¸ö¸´ÔӵĹý³Ì£¬ÆäÖÐÖ÷ÒªÊÇÀûÓý¹Ì¿ºÍÑõÆø·´Ó¦Éú³ÉµÄÒ»Ñõ»¯Ì¼°ÑÌú´ÓÌú¿óʯÖл¹Ô³öÀ´£¬·½³ÌʽΪFe2O3+3CO====2Fe+3CO2ÌúºÍ͵ÄÑÎÈÜÒº·´Ó¦¿É°ÑÍÖû»³öÀ´£¬Èç·½³ÌʽÓÐFe+CuSO4¨TFeSO4+Cu»òFe+CuCl2¨TFeCl2+Cu»ò Fe+Cu£¨NO3£©2¨TFe£¨NO3£©2+Cu£®
£¨3£©ÌúÉúÐâµÄÌõ¼þÊÇÌúÓëÑõÆøºÍˮͬʱ½Ó´¥£¬ËùÒÔ·ÀÖ¹ÌúÉúÐâµÄÔÀí¾ÍÊÇʹÌú¸ô¾ø¿ÕÆøºÍË®£¨»òÑõÆøºÍË®£©£®
£¨4£©¢ÙÓÐͼ¿ÉÖªÌúÍêÈ«·´Ó¦Ê±ÏûºÄµÄÑÎËáÖÊÁ¿ÊÇ146g£®
¢Ú½â£ºÉèÓëÑÎËá·´Ó¦µÄÌúµÄÖÊÁ¿Îªx£®
Fe+2HCl=FeCl2+H2¡ü
56 73
x 146 g¡Á10%="14.6" g
½âµÃ£ºx=11.2g
ÉúÌúÖÐÌúµÄÖÊÁ¿·ÖÊýΪ£º
¡Á100%=93.3%
´ð£ºÉúÌúÖÐÌúµÄÖÊÁ¿·ÖÊýΪ93.3%£®
£¨5£©ÒòΪÈÜÒºÖÊÁ¿²»°üÀ¨ÇâÆøÖÊÁ¿ºÍÊ£ÓàÔÓÖʵÄÖÊÁ¿£¬ËùÒÔ»¹Òª¼õÈ¥ÔÓÖʵÄÖÊÁ¿£®
£¨6£©ÌúºÍÁòËáÍ»¹Î´·´Ó¦Ê±¹ÌÌå¾ÍÊÇÌúÖÊÁ¿Îª12g£¬¹ÊÆðµãÓ¦´Ó×ÝÖáÉÏ12¿ªÊ¼»Æð£»
È»ºóÕҹյ㣬¼´ÌúºÍÁòËáÍÇ¡ºÃÍêÈ«·´Ó¦Ê±ÏûºÄµÄÁòËáÍÈÜÒºÖÊÁ¿¼°¹ÌÌåÖÊÁ¿£¬
ÉèÌúºÍÁòËáÍÇ¡ºÃÍêÈ«·´Ó¦Ê±ÏûºÄÁòËáÍÈÜҺΪy£¬Éú³ÉÍΪz
Fe+CuSO4 ¨TFeSO4 +Cu
56 160 64
11.2g 20%?y z
y=160g
z=12.8g
12gÉúÌúÖÐËùº¬ÔÓÖÊΪ£º12g-11.2g=0.8g
ËùÒÔÌúºÍÁòËáÍÇ¡ºÃÍêÈ«·´Ó¦Ê±¹ÌÌåÖÊÁ¿Îª£º12.8g+0.8g=13.6g
¼´¹Õµã´¦ºá×ø±êֵΪ160£¬×Ý×ø±êֵΪ13.6£¬È»ºó°Ñ¹ÕµãºÍÆðµãÁ¬ÆðÀ´£¬²¢ÇÒÔÚ¹Õµãºó»Ò»ÌõƽÐÐÓÚxÖáµÄÖ±Ïߣ¬¾ÍµÃµ½ÁËËùÒªµÄÇúÏßͼ£®
¹Ê´ð°¸Îª£º£¨1£©CO£»£¨2£©Fe2O3+3CO2Fe+3CO2£¬Fe+CuSO4¨TFeSO4+Cu£»
£¨3£©¿ÕÆøºÍË®£»
£¨4£©¢Ù146£¬¢Ú93.3%£»
£¨5£©ÈÜÒºÖÊÁ¿²»°üÀ¨Ê£ÓàÔÓÖʵÄÖÊÁ¿£¬ËùÒÔ»¹Òª¼õÈ¥ÔÓÖʵÄÖÊÁ¿£»
£¨6£©
´ËÌâÊÇ×ÛºÏÐÔ½ÏÇ¿µÄÌâÄ¿£¬°üÀ¨µÄÎÊÌâ½Ï¶à£¬Éæ¼°µÄ֪ʶÃæºÜ¹ã£¬ÊôÓÚÄѶȽϴóµÄÌâÄ¿£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿