ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ (7·Ö)ÒÔÏ¿òͼÖеÄÎïÖʾùΪ³õÖл¯Ñ§Öеij£¼ûÎïÖÊ£¬ÆäÖмס¢ÒÒ¡¢±û¡¢¶¡¡¢Îì¾ùΪµ¥ÖÊ£¬³£ÎÂÏ£¬¶¡ÎªºÚÉ«¹ÌÌ壬ÎìΪ×ϺìÉ«½ðÊô£®Å©ÒµÉϳ£ÓÃF¸ÄÁ¼ËáÐÔÍÁÈÀ£®³£ÎÂÏ£¬GÊÇÒ»ÖÖ¾ßÓд̼¤ÐÔÆøζµÄÆøÌ壬ÆäË®ÈÜÒºÏÔ¼îÐÔ£¬¹¤ÒµÉÏÓü׺ͱû»¯ºÏÖƱ¸G£®
£¨1£©Ð´³ö¶¡¡¢BºÍHµÄ»¯Ñ§Ê½£º
¶¡ B H
£¨2£©C¡¢E»¯Ñ§ÐÔÖʲ»Í¬£¬ÊÇÒòΪ£º
£¨3£©Ð´³öA·Ö½âΪ¼×ºÍÒҵĻ¯Ñ§·½³Ìʽ£º___________________
£¨4£©Ð´³öF¡úGµÄ»¯Ñ§·½³Ìʽ£º________
£¨5£©¼×ºÍ±û»¯ºÏÖƱ¸G£¬¼×ºÍ±ûµÄÖÊÁ¿Ö®±ÈΪ£º
¡¾´ð°¸¡¿£¨1£©C CaCO 3 CuO £¨2£©·Ö×Ó¹¹³É²»Í¬ £¨3£©2H2O2H2¡ü+O2¡ü
£¨4£©Ca(OH) 2+(NH4) 2SO4 CaSO4+2H2O +2NH3¡ü £¨5£©3:14
¡¾½âÎö¡¿
ÊÔÌâ·ÖÎö£º¸ÃÌâÐÍΪÍƶÏÌ⣬Ö÷ÒªµÄ¼¼ÇÉÔÚÓÚÕÒ³öÌâÄ¿µÄÍ»ÆÆ¿Ú£¬¾ÍÊÇ×îÈÝÒ×È·¶¨µÄÎïÖÊ£¬È»ºó¸ù¾ÝÈ·¶¨µÄÎïÖÊÒÀ´ÎÈ·¶¨¼´¿É£¬±¾ÌâÖ÷ÒªÊ×ÏÈÕÒµ½£ºÎìΪ×ϺìÉ«½ðÊôΪͣ¬¶¡ÎªºÚÉ«¹ÌÌåΪ̼£¬Å©ÒµÉϳ£ÓÃF¸ÄÁ¼ËáÐÔÍÁÈÀΪÇâÑõ»¯¸Æ£¬GÊÇÒ»ÖÖ¾ßÓд̼¤ÐÔÆøζµÄÆøÌ壬ÆäË®ÈÜÒºÏÔ¼îÐÔÒ»°ãΪ°±Æø£¬È»ºó¸ù¾ÝÏà¹ØµÄÐÔÖʺͱ仯¿ÉÒÔÒÀ´ÎÈ·¶¨¡£