ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿Ë®ÊÇÉúÃüÖ®Ô´£¬±£»¤Ë®×ÊÔ´ÊÇ¡°¼ùÐÐÂÌÉ«Éú»î¡±µÄÖØÒªÄÚÈÝÖ®Ò»£¬ Çë»Ø´ðÏÂÁÐÓйØË®µÄÎÊÌâ:
(1)ÏÂÁÐÐÐΪÊôÓÚ½ÚÔ¼ÓÃË®µÄÊÇ____________(ÌîÐòºÅ);
A Ï´Ôè²ÁÏãÔíʱ¹ØÉÏÅçÍ·
B ²»¼ä¶Ï·ÅˮˢÑÀ
C ÓÃ×ÔÀ´Ë®²»¶ÏΪÎ÷¹Ï³åË®½µÎÂ
D ÓÃÏ´ÒÂË®³å²ÞËù
(2)¢Ùˮͨµç¿É·¢Éú·Ö½â·´Ó¦£¬µç½âÒ»¶¨Á¿µÄË®£¬Õý¼«²úÉúµÄÆøÌåÊÇ_________________(д»¯Ñ§Ê½),µ±Õý¼«²úÉúµÄÆøÌåΪ5mLʱ£¬¸º¼«²úÉúµÄÆøÌåÌå»ýΪ__________________mL¡£
¢ÚÖÆÈ¡ÒûÓÃË®³£ÓõÄÏû¶¾¼ÁClO2µÄ»¯Ñ§·½³ÌʽΪ: ¡£ XµÄ»¯Ñ§Ê½Îª___________________Äã×÷³ö´ËÅжϵÄÒÀ¾ÝÊÇ___________________________¡£
(3)¢ÙÈôÒª¼ì²âijºÓË®µÄËá¼î¶È£¬¿ÉÑ¡ÓÃ____________________ (Ìî×ÖĸÐòºÅ)¡£
A ·Ó̪ÊÔÒº
B pHÊÔÖ½
C ʯÈïÊÔÒº
¢ÚÉú»îÖг£ÓÃ____________________µÄ·½·¨£¬½µµÍË®µÄÓ²¶È£¬Í¬Ê±ÓÖÄÜÏû¶¾É±¾ú¡£
¡¾´ð°¸¡¿A D O2 10 NaCl ·´Ó¦Ç°ºóÔ×ÓµÄÖÖÀàºÍÊýÄ¿²»±ä B Öó·Ð
¡¾½âÎö¡¿
£¨1£©A¡¢Ï´Ôè²ÁÏãÔíʱ¹ØÉÏÅçÍ·£¬ÄܽÚÔ¼ÓÃË®¡£AÕýÈ·£»
B¡¢²»¼ä¶Ï·ÅˮˢÑÀ£¬»áÔì³ÉË®µÄÀË·Ñ¡£²»ÊôÓÚ½ÚÔ¼ÓÃË®¡£B´íÎó£»
C¡¢ÓÃ×ÔÀ´Ë®²»¶ÏΪÎ÷¹Ï³åË®½µÎ£¬»áÔì³ÉË®µÄÀË·Ñ£¬²»ÊôÓÚ½ÚÔ¼ÓÃË®¡£C´íÎó£»
D¡¢ÓÃÏ´ÒÂË®³å²ÞËù£¬Ò»Ë®¶àÓã¬ÄܽÚÔ¼ÓÃË®¡£DÕýÈ·¡£
¹Ê´ð°¸Îª£ºAD£»
£¨2£©¢Ùˮͨµç¿É·¢Éú·Ö½â·´Ó¦£¬µç½âÒ»¶¨Á¿µÄË®£¬ÓÉÓÚÔÚµç½âˮʱ£¬Õý¼«²úÉúÑõÆø£¬¸º¼«²úÉúÇâÆø£¬ÇâÆøºÍÑõÆøµÄÌå»ý±ÈΪ2:1¡£ËùÒÔÕý¼«²úÉúµÄÆøÌåÊÇO2¡£µ±Õý¼«²úÉúµÄÆøÌåΪ5mLʱ£¬¸º¼«²úÉúµÄÆøÌåÌå»ýΪ10mL¡£¹Ê´ð°¸Îª£ºO2¡¢10£»
¢ÚÖÆÈ¡ÒûÓÃË®³£ÓõÄÏû¶¾¼ÁClO2µÄ»¯Ñ§·½³ÌʽΪ£ºCl2+2NaClO2=2ClO2+2X¡£ÓÉ·´Ó¦µÄ»¯Ñ§·½³Ìʽ¿ÉÖª£¬·´Ó¦Ç°ÓÐ2¸öÄÆÔ×Ó¡¢4¸öÂÈÔ×Ó¡¢4¸öÑõÔ×Ó£¬·´Ó¦ºóÓÐ2¸öÂÈÔ×Ó£¬4¸öÑõÔ×Ó£¬Ïà²î2¸öÄÆÔ×ÓºÍ2¸öÂÈÔ×Ó¡£ÔòXµÄ»¯Ñ§Ê½ÎªNaCl¡£×÷³ö´ËÅжϵÄÒÀ¾ÝÊǸù¾ÝÖÊÁ¿Êغ㶨ÂÉ¿ÉÖª£¬·´Ó¦Ç°ºóÔ×ÓµÄÖÖÀ༰ÊýÄ¿²»±ä¡£¹Ê´ð°¸Îª£ºNaCl¡¢·´Ó¦Ç°ºóÔ×ÓµÄÖÖÀ༰ÊýÄ¿²»±ä£»
£¨3£©¢ÙÈôÒª¼ì²âijºÓË®µÄËá¼î¶È£¬¿ÉÑ¡ÓÃpHÊÔÖ½£¬·Ó̪ÊÔÒººÍʯÈïÊÔÒºÖ»ÄܲⶨÈÜÒºµÄËá¼îÐÔ¡£¹Ê´ð°¸Îª£ºB£»
¢ÚÉú»îÖг£ÓÃÖó·ÐµÄ·½·¨£¬½µµÍË®µÄÓ²¶È£¬Í¬Ê±ÓÖÄÜÏû¶¾É±¾ú¡£¹Ê´ð°¸Îª£ºÖó·Ð¡£