ÌâÄ¿ÄÚÈÝ

ij¹¤³§Ã¿ÌìÅųö·ÏË®1000Ã×3£¬ÆäÖÐÿÁ¢·½Ã×·ÏË®Öк¬ÂÈÆø£¨Cl2£©35.5¿Ë£¬º¬ÑÎËᣨHCl£©36.5¿Ë£®Ö±½ÓÅŷŽ«ÒýÆðË®ÎÛȾ£¬ÐèÏÈÓÃÑÇÁòËáÄÆ£¨Na2SO3£©³ýÈ¥Cl2£¬·´Ó¦·½³ÌʽΪ£º
Na2SO3+Cl2+H2O¨TNa2SO4+2HCl£¬ÔÙÓÃNaOHÖкÍÑÎËᣮ
ÊÔÎÊ£¨1£©¸Ã1000Ã×3·ÏË®Öк¬HClµÄÖÊÁ¿Îª
 
¿Ë£»·ÏË®µÄPH
 
7£¨Ñ¡Ì¡°£¾¡±¡¢¡°=¡±¡¢¡°£¼¡±£©
£¨2£©¸Ã³§Ã¿ÌìÐèÖÊÁ¿·ÖÊýΪ9%µÄNa2SO3ÈÜÒº¶àÉÙ¿Ë£¿
£¨3£©ÎªÊ¹·ÏË®³ÊÖÐÐÔ£¬ÐèNaOH¹ÌÌå¶àÉÙ¿Ë£¿
·ÖÎö£º¸ù¾Ý·ÏË®ÖÐÂÈÆøµÄÖÊÁ¿£¬ÓÉ»¯Ñ§·½³ÌʽÇóµÃHClµÄÖÊÁ¿ºÍNa2SO3£¬ÔÙÇóµÃNa2SO3ÈÜÒºµÄÖÊÁ¿ºÍÐèNaOH¹ÌÌåµÄÖÊÁ¿£®
½â´ð£º½â£º£¨1£©3.65¡Ál04 £¼
£¨2£©ÉèÐèÒª9%Na2S03 ÖÊÁ¿Îªx£¬Éú³ÉÑÎËáÖÊÁ¿y£®Ôò
Na2S03+C12+H20¨TNa2S04+2HCl
126   71               73 
9%X   35500g           Y
126
x
=
71
35500g

x=7.0¡Á105
71
35500g
=
73
y

y=3.65¡Á104g
£¨3£©ÑÎËáµÄ×ÜÖÊÁ¿£º7.3 x 104¿Ë
ÉèÐèNaOH z¿Ë
 HCl+NaOH¨TNaCl+H20
 36.5       40
7.3¡Ál04g   z
36.5
7.3¡Ál04g
=
40
z

z=8.0¡Á104g
´ð£ºÐè9%µÄNa2S03ÈÜÒº7.0¡Á105¿Ë£¬ÐèNaOH¹ÌÌå8.0¡Á104¿Ë£®
µãÆÀ£º¸ù¾Ý»¯Ñ§·½³Ìʽ¼ÆË㣬Ê×ÏÈҪд³öÕýÈ·µÄ»¯Ñ§·½³Ìʽ£¬È»ºóÔÙ¸ù¾ÝÒÑÖªÁ¿Î´ÖªÁ¿ÇóË㣮
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
¾«Ó¢¼Ò½ÌÍøA£®Ä³ÕòÓÐ×ùÁòË᳧£¬É豸¼òª£¬¼¼Êõ³Â¾É£¬¸Ã³§Ã¿ÌìÅÅ·Å´óÁ¿º¬SO2µÄ·ÏÆøºÍº¬H2SO4µÄËáÐÔ·ÏË®£®µ±µØµÄÆäËû¹¤³§ºÍ¾ÓÃñ¾ùÓÃú̿×÷ȼÁÏ£®Ö»ÒªÏÂÓê¾ÍÏÂËáÓ꣬¶Ô¸ÃÕò»·¾³Ôì³É¼«´óÆÆ»µ£®
£¨1£©·ÖÎö¸ÃÕòÏÂËáÓêµÄÔ­Òò£º
 
£»
£¨2£©¾ÙÒ»Àý˵Ã÷ËáÓê¶Ô»·¾³Ôì³ÉµÄΣº¦£º
 
£»
£¨3£©¶þÑõ»¯ÁòÊÇ´óÆøÎÛȾÎÈÜÓÚË®ËùµÃÈÜÒºµÄpH
 
7£¨Ìî¡°´óÓÚ¡±¡¢¡°Ð¡ÓÚ¡±»ò¡°µÈÓÚ¡±£©£»¶þÑõ»¯ÁòÆøÌå¿ÉÓÃÇâÑõ»¯ÄÆÈÜÒºÀ´ÎüÊÕ£¬Çëд³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
 
£»
£¨4£©¸ÃÕòijÖÐѧ»·±£Ð¡×éÌá³öÁËÖÎÀíËáÓêµÄÏÂÁдëÊ©£¬ÄãÈÏΪÆäÖв»Í×µÄÊÇ
 

A£®½«ÁòË᳧°áÀë¸ÃÕò
B£®½¨Òé»·±£²¿ÃÅÏÂÁîÕû¸Ä
C£®½«ÁòË᳧ÅųöµÄ·ÏÆøÖеÄSO2´¦ÀíºóÅÅ·Å
D£®¹¤³§ºÍ¾ÓÃñ¸ÄÓýÏÇå½àµÄȼÁÏ
£¨5£©¿ÉÓÃÊìʯ»ÒÀ´´¦ÀíÁòË᳧ÅųöµÄËáÐÔ·ÏË®£¬´¦ÀíÔ­ÀíµÄ»¯Ñ§·½³ÌʽÊÇ
 
£»
£¨6£©Å¨ÁòËáŪµ½ÊÖÉϺóÓ¦Á¢¼´ÓÃË®³åÏ´£¬È»ºóÍ¿ÉÏ̼ËáÇâÄÆ£®ÈôÊÇÏ¡ÁòËáŪµ½ÊÖÉÏ£¬
 
£¨Ìî¡°ÐèÒª¡±»ò¡°²»ÐèÒª¡±£©ÕâÑù×ö£¬ÀíÓÉÊÇ
 
£®
B£®¾Ý±¨µÀ£¬´Ó2005Äê1ÔÂ1ÈÕÆ𣬹óÖÝÊ¡¸÷µØ»·±£²¿ÃŽ«¶ÔʵÑéÊÒÀàÎÛȾʵʩÑϸñµÄ»·¾³¼à¹Ü£®ÓÉÓÚѧУ»¯Ñ§ÊµÑéÊÒÒªÅŷųɷָ´ÔÓµÄÎÛȾÎËùÒÔÒ²±»ÁÐΪ»·¾³¼à¹Ü·¶Î§£®Ä³Ð£»¯Ñ§ÐËȤС×éµÄͬѧÔÚ¼×ʵÑéÊÒÖнøÐÐÁËÑõÆø·Ö±ðÓë̼¡¢Áò¡¢Ìú·´Ó¦µÄʵÑéºó£¬ÎªÁ˽â¸ÃʵÑé²úÉúµÄÆøÌå¶Ô¿ÕÆø³É·ÖÔì³ÉµÄÓ°Ï죬½Ó×ÅÉè¼ÆÁËÈçÏÂʵÑé×°ÖýøÐÐʵÑ飨ͼÖжà¿×ÇòÅݵÄ×÷ÓÃÊÇ£ºÔö´óÆøÌåÓëÈÜÒºµÄ½Ó´¥Ãæ»ý£¬Ê¹·´Ó¦³ä·Ö½øÐУ©£®Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÊµÑéÔÚûÓÐÊÜÎÛȾµÄÒÒʵÑéÊÒÖнøÐУ¬È¡³öÊÊÁ¿¼×ʵÑéÊÒÖпÕÆøÑùÆ·µÄ·½·¨ÊÇ
 
£»
£¨2£©½«È¡µÃµÄ¿ÕÆøÑùÆ·°´ÈçͼËùʾµÄ×°ÖýøÐÐʵÑé²â¶¨£º×°ÖÃAµÄ×÷ÓÃÊÇ
 
£¬ÆäÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
 
£»×°ÖÃBÖеÄÏÖÏóÊÇ
 
£»×°ÖÃCµÄ×÷ÓÃÊÇ
 
£»
£¨3£©ÈôͨÈë¿ÕÆøÑùÆ·100mL£¬ÊµÑé½áÊøºó£¬Á¿Í²ÖÐÒºÌåµÄÌå»ýΪ99mL£¨µ¼¹ÜÄÚÒºÌåºöÂÔ²»¼Æ£©£¬ËµÃ÷×°ÖÃ
 
ÖÐÎüÊÕÁË1mLÆøÌ壮ÈôÕâЩÆøÌå´óÁ¿Åŷŵ½¿ÕÆøÖУ¬Òò²úÉú
 
£¬»á¶Ô»·¾³Ôì³É²»ÀûÓ°Ï죻
£¨4£©Çëд³öÄãÔÚ×ö»¯Ñ§ÊµÑéʱ£¬¼õÉÙʵÑé¶Ô»·¾³ÎÛȾµÄÒ»ÖÖ×ö·¨£º
 
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø