ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿Í¨¹ýÒ»ÄêµÄ»¯Ñ§Ñ§Ï°£¬ÄãÒѾÕÆÎÕÁËʵÑéÊÒÖÆÈ¡ÆøÌåµÄÓйعæÂÉ£¬ÒÔÏÂÊÇÀÏʦÌṩµÄһЩʵÑé×°Öá£Çë½áºÏÈçͼ»Ø´ðÎÊÌ⣺
£¨1£©Ð´³öͼÖбêºÅµÄÒÇÆ÷Ãû³Æ£ºa______b______¡£
£¨2£©Ð´³öʵÑéÊÒÓÃA×°ÖÃÖÆÈ¡ÑõÆøµÄ»¯Ñ§·½³Ìʽ______¡£
£¨3£©Í¨¹ý²éÔÄ×ÊÁϵÃÖª£º¢Ù°±ÆøNH3ÊÇÒ»ÖÖÃܶȱȿÕÆøСÇÒ¼«Ò×ÈÜÓÚË®µÄÆøÌ壬ÆäË®ÈÜÒº³ÆΪ°±Ë®£»¢Ú°±ÆøÔÚ¼ÓÈÈÌõ¼þÏÂÄÜÓëÑõ»¯Í·´Ó¦Éú³ÉÍ¡¢Ë®ºÍ¿ÕÆøÖк¬Á¿×î¶àµÄÆøÌ塣С·¼Í¬Ñ§¼ÓÈÈÂÈ»¯ï§ºÍÇâÑõ»¯¸ÆµÄ¹ÌÌå»ìºÏÎïÖÆÈ¡°±Æø£¬ËýӦѡÔñµÄ ÖÆȡװÖÃ×éºÏÊÇ _______¡££¨Ìî×Öĸ±àºÅ£©
£¨4£©Çëд³ö°±ÆøºÍÑõ»¯Í·´Ó¦µÄ»¯Ñ§·½³Ìʽ______¡£
¡¾´ð°¸¡¿·ÖҺ©¶· ÊÔ¹Ü 2H2O22H2O+O2¡ü BE 2NH3£«3CuO
3Cu£«3H2O£«N2
¡¾½âÎö¡¿
£¨1£©Ð´³öͼÖбêºÅµÄÒÇÆ÷Ãû³Æ£ºa·Ö½â©¶·bÊԹܣ»
£¨2£©ÊµÑéÊÒÓùÌÒº·¢Éú×°ÖÃAÖÆÈ¡ÑõÆø£¬Ö»ÄÜÓùýÑõ»¯ÇâÈÜÒººÍ¶þÑõ»¯Ã̹ÌÌå»ìºÏÖÆÑõÆø£¬·´Ó¦ÔÀíΪ£º2H2O22H2O+O2¡ü£»
£¨3£©Ð¡·¼Í¬Ñ§¼ÓÈÈÂÈ»¯ï§ºÍÇâÑõ»¯¸ÆµÄ¹ÌÌå»ìºÏÎïÖÆÈ¡°±Æø£¬ËýӦѡÔñ¹ÌÌå¼ÓÈÈ×°ÖÃB£¬
°±ÆøNH3ÊÇÒ»ÖÖÃܶȱȿÕÆøСÇÒ¼«Ò×ÈÜÓÚË®µÄÆøÌ壬ÆäË®ÈÜÒº³ÆΪ°±Ë®£¬ÓÃÏòÏÂÅÅ¿ÕÆø·¨ÊÕ¼¯°±Æø£¬Ñ¡Ôñ×°ÖÃE¡£
£¨4£©°±ÆøÔÚ¼ÓÈÈÌõ¼þÏÂÄÜÓëÑõ»¯Í·´Ó¦Éú³ÉÍ¡¢Ë®ºÍµªÆø£¬°±ÆøºÍÑõ»¯Í·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º2NH3£«3CuO3Cu£«3H2O£«N2¡£

¡¾ÌâÄ¿¡¿ÑõÆøºÍÑõµÄ»¯ºÏÎïÔÚ¹¤Å©ÒµÉú²ú¡¢Éú»îÖÐÓй㷺µÄÓ¦Óá£
£¨Ò»£©¹¤ÒµÖÆÑõÆø
£¨1£©¹¤ÒµÉÏÓÿÕÆøÖÆÈ¡ÑõÆø¡£¿ÕÆøÖÐÖ÷Òª×é·ÖµÄ·ÐµãÈçÏÂ±í£º
×é·Ö | µªÆø | ÑõÆø |
·Ðµã£¨¡æ£© | -196 | -183 |
¸ù¾ÝÑõÆøºÍµªÆøµÄ________²»Í¬£¬½«ÒºÌ¬¿ÕÆø·ÖÀëµÃµ½ÑõÆø¡£
£¨2£©½Ò¿ªÊ¢ÓÐҺ̬¿ÕÆøµÄ±£ÎÂÆ¿¸Ç£¬²¢½«È¼×ŵÄľÌõÖÃÓÚÆ¿¿ÚÉÏ·½£¬¿É¹Û²ìµ½__________£¨Ìî×Öĸ£©¡£
A ľÌõϨÃð
B ÌõȼÉÕ¸üÍú
C ľÌõÏÈϨÃ𣬺óȼÉÕ¸üÍú
£¨¶þ£©Éú»îÖеÄÑõÆø
£¨3£©Ä³¼ÒÍ¥ÖÆÑõ»úÉÏÓÐʪ»¯Æ¿×°Öá£ÈËÎüÑõʱ¹Û²ìµ½Æ¿ÖÐÓÐÆøÅÝ¡£Êª»¯Æ¿×°ÖÃÀàËÆÓÚÏÂͼ¡£¹ØÓÚ¸Ã×°Öã¬ÏÂÁÐ˵·¨ÕýÈ·µÄÓÐ____________£¨Ìî×Öĸ£©¡£
A bµ¼¹ÜÁ¬½ÓÖÆÑõ»ú
B bµ¼¹ÜÁ¬½ÓÈËÎüÑõÆøµÄËÜÁϹÜ
C ʹÓøÃ×°ÖÿÉÒÔ¹Û²âÊÇ·ñÓÐÑõÆøÊä³ö
D ʹÓøÃ×°ÖÿÉÒÔ¹Û²âÑõÆøÊä³öµÄËÙÂÊ
£¨4£©ÏÂÁÐÎïÖÊÖк¬ÓÐÑõ·Ö×ÓµÄÓÐ_______£¨Ìî±àºÅ£©¡£
¢ÙCO2 ¢Úº£Ë® ¢ÛH2O2 ¢Ü¿ÕÆø ¢ÝÒºÑõ ¢Þ¸ßÃÌËá¼Ø
£¨Èý£©ÓæÒµÖÆÑõÆø
£¨5£©ÔËÊä»îÓãʱ£¬ÓùýÑõ»¯¸Æ£¨CaO2£©¿ÉÔö¼ÓË®Öк¬ÑõÁ¿¡£ÁªÏëµ½¹ýÑõ»¯¸Æ£¨CaO2£©µÄ´Ë×÷Óã¬Ð¡Ã÷ÔÚʵÑéʱ£¬Ìá³öÏÂÁвÂÏë²¢ÓÃÏÂͼװÖýøÐÐʵÑ飺
£¨²ÂÏ룩CaO2ÓëH2O·´Ó¦ÓÃÓÚʵÑéÊÒÖÆÈ¡ÑõÆø¡£
£¨ÊµÑé¹ý³Ì£©
¢Ù____________£¨ÌîһʵÑé²½Ö裩£»
¢ÚÏòÊÔ¹ÜÖмÓÈëCaO2ºÍH2Oºó£¬Óм«Î¢Á¿Ï¸Ð¡ÆøÅÝ»ºÂý·Å³ö¡£½«µ¼¹ÜÉìÈ뼯ÆøÆ¿ÖУ¬¼¸ºõÊÕ¼¯²»µ½ÆøÌå¡£·ÅÖõ½µÚ¶þÌ죬¼¯ÆøÆ¿ÖÐÖ»ÊÕ¼¯µ½ÉÙÁ¿ÆøÌ壬Õðµ´ÊԹܺóÈÔÓм«Î¢Á¿Ï¸Ð¡ÆøÅÝ»ºÂý·Å³ö¡£
£¨ÊµÑé½áÂÛ£©CaO2ÓëH2O·´Ó¦__________£¨Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±£©ÓÃÓÚʵÑéÊÒÖÆÈ¡ÑõÆø¡£
£¨·ÖÎöÓ뷴˼£©
¢Ù½áºÏÉÏÊöʵÑ飬СÃ÷ÈÏΪÔËÊä»îÓãʱÓÃCaO2×öÔöÑõ¼ÁµÄÓŵãÊÇ_______________¡£
¢ÚСÃ÷¾õµÃ´¢´æCaO2£¬×¢ÒâµÄÎÊÌâÓÐ______________________¡£
¢ÛͬѧÃǶÔCaO2ÓëH2O·´Ó¦µÄÉú³ÉÎï²ÂÏëÈçÏ£º¢ñ.ÇâÑõ»¯¸ÆºÍÑõÆø ¢ò.̼Ëá¸ÆºÍÑõÆø
ÄãÈÏΪ²ÂÏë_________£¨ÌîÐòºÅ£©Ò»¶¨ÊÇ´íÎóµÄ£¬ÀíÓÉÊÇ_____________________¡£
°´ÕÕ²ÂÏë¢ñ£¬Ð´³öCaO2ÓëH2O·´Ó¦µÄ»¯Ñ§±í´ïʽ_______________________¡£
£¨ËÄ£©CaO2Æ·ÖʵÄÌÖÂÛ
СÃ÷¹ºµÃÓÃÓÚÔöÑõµÄCaO2²úÆ·Ò»°ü£¨ÔÓÖʲ»º¬¸ÆÔªËØ£©£¬¸Ã°ü±êÇ©ÈçͼËùʾ¡£ÊÔ¼ÆË㣺
£¨6£©CaO2ÖиÆÔªËØÓëÑõÔªËصÄÖÊÁ¿±ÈΪ____________¡£________gCaO2Óë24.5g KClO3Öк¬ÑõÔªËصÄÖÊÁ¿Ï൱¡£´ËÒ»°ü²úÆ·ÖÁÉÙº¬CaO2________g¡£
£¨7£©×÷ΪÏà¶ÔÔ×ÓÖÊÁ¿±ê×¼µÄ̼Ô×ÓÖÊÁ¿Îª2.0¡Á1026kg£¬Ä³ÖÖÑõÔ×ÓµÄÏà¶ÔÔ×ÓÖÊÁ¿Îª18£¬Ôò¸ÃÑõÔ×ÓÖÊÁ¿Îª___________¡Á1026kg¡£
¡¾ÌâÄ¿¡¿ÎÒÊÐʯ»Òʯ×ÊÔ´·á¸»£¬Ä³¿ÎÍâС×éͬѧΪÁ˲ⶨʯ»ÒʯÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊý£¬È¡Ä³µØʯ»ÒʯÑùÆ·10.0gÓÚÉÕ±ÖУ¬½«100gÏ¡ÑÎËá·Ö5´Î¼ÓÈëÉÕ±ÖУ¬³ä·Ö·´Ó¦ºó(ÔÓÖʲ»ÓëÏ¡ÑÎËá·´Ó¦)£¬²âµÃÊ£Óà¹ÌÌåµÄÖÊÁ¿¼Ç¼ÈçÏ£®
´ÎÊý | 1 | 2 | 3 | 4 | 5 |
¼ÓÈëÏ¡ÑÎËáÖÊÁ¿/g | 20 | 20 | 20 | 20 | 20 |
Ê£Óà¹ÌÌåÖÊÁ¿/g | 8.0 | 6.0 | 4.0 | 2.5 | X |
Çë¼ÆË㣺(1)XµÄֵΪ__________£®
(2)¸Ãʯ»ÒʯÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊýΪ_____________
(3)ËùÓÃÏ¡ÑÎËáÈÜÖʵÄÖÊÁ¿·ÖÊýΪ________£®(д³ö¼ÆËã¹ý³Ì)