ÌâÄ¿ÄÚÈÝ
¡°æ϶ðÈýºÅ¡±·É´¬µÄ³É¹¦·¢ÉäÊÇÎÒ¹úº½ÌìÊÂÒµµÄÓÖÒ»Àï³Ì±®£®½ðÊô¹ýÑõ»¯ÎïµÈ¿É×÷ÓîÖæ·É´¬»òDZˮͧÖеÄÑõÆøÔÙÉú¼Á£¬È磺¹ýÑõ»¯ÄÆ£¨Na2O2£©ÔÚ³£ÎÂÏÂÄÜÓëÈ˺ô³öµÄ¶þÑõ»¯Ì¼·´Ó¦Éú³ÉÑõÆøºÍ̼ËáÄÆ£»ÎªÁËÑéÖ¤¸Ã·´Ó¦ÖÐÑõÆøµÄ²úÉú£¬Ä³ÐËȤС×éµÄͬѧÉè¼ÆÁËÈçͼËùʾµÄʵÑ飮
£¨1£©ÎªÁËÈ·¶¨CO2¸úNa2O2·´Ó¦²úÉúµÄÆøÌåÊÇÑõÆø£¬×îºó»¹Òª²ÉÓõÄÑé֤ʵÑé²Ù×÷ÊÇÔÚDµ¼¹Ü´¦·ÅÖÃÒ»¸ù £®
£¨2£© £¨Ìî¡°ÏÖÏó¡±£©ËµÃ÷¶þÑõ»¯Ì¼Òѱ»¹ýÑõ»¯ÄÆÍêÈ«ÎüÊÕ£®
£¨3£©ÈôÿÈËÿÌì²úÉúµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª2.2ǧ¿Ë£¬ÈôÓùýÑõ»¯Äƽ«ÕâЩ¶þÑõ»¯Ì¼È«²¿ÎüÊÕ£¬ÔòÀíÂÛÉϿɲúÉúÑõÆø¶¼ÉÙǧ¿Ë£¿£¨Ð´³ö¼ÆËã¹ý³Ì£©
£¨4£©ÔÚʵÑéÊÒÓøßÃÌËá¼Ø¼ÓÈÈÒ²ÄܲúÉúÑõÆø£¬Ð¡ºìͬѧ½«16gµÄ¸ßÃÌËá¼Ø·ÅÔÚÊÔ¹ÜÖмÓÈÈÒ»¶Îʱ¼äºó£¬ÀäÈ´£¬³ÆµÃÊ£ÓàÎïÖʵÄÖÊÁ¿Îª14.4g£®
¢Ù´ó¼Ò·×·×²ÂÏëËùµÃ¹ÌÌåÎïÖʵijɷ֣¨Ð´ÎïÖʵĻ¯Ñ§Ê½£©£º
²ÂÏëÒ»£º
²ÂÏë¶þ£º
¢Ú¾¹ý¼ÆËãÈ·¶¨²ÂÏë ÊÇÕýÈ·µÄ£®£¨²»ÐèҪд³ö¼ÆËã¹ý³Ì£©
£¨1£©ÎªÁËÈ·¶¨CO2¸úNa2O2·´Ó¦²úÉúµÄÆøÌåÊÇÑõÆø£¬×îºó»¹Òª²ÉÓõÄÑé֤ʵÑé²Ù×÷ÊÇÔÚDµ¼¹Ü´¦·ÅÖÃÒ»¸ù
£¨2£©
£¨3£©ÈôÿÈËÿÌì²úÉúµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª2.2ǧ¿Ë£¬ÈôÓùýÑõ»¯Äƽ«ÕâЩ¶þÑõ»¯Ì¼È«²¿ÎüÊÕ£¬ÔòÀíÂÛÉϿɲúÉúÑõÆø¶¼ÉÙǧ¿Ë£¿£¨Ð´³ö¼ÆËã¹ý³Ì£©
£¨4£©ÔÚʵÑéÊÒÓøßÃÌËá¼Ø¼ÓÈÈÒ²ÄܲúÉúÑõÆø£¬Ð¡ºìͬѧ½«16gµÄ¸ßÃÌËá¼Ø·ÅÔÚÊÔ¹ÜÖмÓÈÈÒ»¶Îʱ¼äºó£¬ÀäÈ´£¬³ÆµÃÊ£ÓàÎïÖʵÄÖÊÁ¿Îª14.4g£®
¢Ù´ó¼Ò·×·×²ÂÏëËùµÃ¹ÌÌåÎïÖʵijɷ֣¨Ð´ÎïÖʵĻ¯Ñ§Ê½£©£º
²ÂÏëÒ»£º
²ÂÏë¶þ£º
¢Ú¾¹ý¼ÆËãÈ·¶¨²ÂÏë
·ÖÎö£º£¨1£©¸ù¾ÝÑõÆøµÄÐÔÖÊÀ´Íê³É½â´ð£»
£¨2£©ÀûÓöþÑõ»¯Ì¼ÄÜʹ³ÎÇåʯ»ÒË®±ä»ë×ǵÄÐÔÖʻشð£®
£¨3£©ÀûÓû¯Ñ§·½³Ìʽ½øÐмÆË㣬д³ö¼ÆËã¹ý³Ì£»
£¨4£©¸ù¾Ý¸ßÃÌËá¼ØÊÜÈÈ·Ö½âµÄ»¯Ñ§·½³Ìʽ£¬¿ÉµÃÖª·´Ó¦ÖиßÃÌËá¼ØÓëÑõÆøµÄÖÊÁ¿¹Øϵ£¬ÔÙÓÉÉú³ÉÑõÆøµÄÖÊÁ¿¼´¿É¼ÆËãËùÐèÒª¸ßÃÌËá¼ØµÄÖÊÁ¿£®Ôò¿ÉÍƲ⣺¸ßÃÌËá¼ØÍêÈ«·´Ó¦»ò²»ÍêÈ«·´Ó¦£¬¶øÌá³ö²ÂÏ룻¾¹ý¼ÆËãÈ·¶¨Äĸö²ÂÏëÊÇÕýÈ·µÄ£®
£¨2£©ÀûÓöþÑõ»¯Ì¼ÄÜʹ³ÎÇåʯ»ÒË®±ä»ë×ǵÄÐÔÖʻشð£®
£¨3£©ÀûÓû¯Ñ§·½³Ìʽ½øÐмÆË㣬д³ö¼ÆËã¹ý³Ì£»
£¨4£©¸ù¾Ý¸ßÃÌËá¼ØÊÜÈÈ·Ö½âµÄ»¯Ñ§·½³Ìʽ£¬¿ÉµÃÖª·´Ó¦ÖиßÃÌËá¼ØÓëÑõÆøµÄÖÊÁ¿¹Øϵ£¬ÔÙÓÉÉú³ÉÑõÆøµÄÖÊÁ¿¼´¿É¼ÆËãËùÐèÒª¸ßÃÌËá¼ØµÄÖÊÁ¿£®Ôò¿ÉÍƲ⣺¸ßÃÌËá¼ØÍêÈ«·´Ó¦»ò²»ÍêÈ«·´Ó¦£¬¶øÌá³ö²ÂÏ룻¾¹ý¼ÆËãÈ·¶¨Äĸö²ÂÏëÊÇÕýÈ·µÄ£®
½â´ð£º½â£º
£¨1£©ÒòΪÑõÆøÄÜÖ§³ÖȼÉÕ£¬¹Ê¿ÉÒÔÓôø»ðÐǵÄľÌõ·ÅÔÚ¼¯ÆøÆ¿¿Ú¼ìÑéÑõÆø£»
£¨2£©Èç¹û³ÎÇåʯ»ÒˮûÓб仯£¬Ôò˵Ã÷¶þÑõ»¯Ì¼Òѱ»¹ýÑõ»¯ÄÆÍêÈ«ÎüÊÕ£®
£¨3£©ÈôÿÈËÿÌì²úÉúµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª2.2ǧ¿Ë£¬Ôò¸ù¾Ý»¯Ñ§·½³Ìʽ¿ÉÒÔ¼ÆË㣮
½â£ºÉèÀíÂÛÉϿɲúÉúÑõÆøµÄÖÊÁ¿Îªx£¬
2Na2O2+2CO2=2Na2CO3+O2
88 32
2.2kg x
Ôò
=
£¬½âµÃx=0.8kg
´ð£ºÔòÀíÂÛÉϿɲúÉúÑõÆø0.8ǧ¿Ë£®
£¨4£©¢Ù¸ù¾Ý»¯Ñ§·½³Ìʽ2KMnO4
K2MnO4+MnO2+O2¡ü£¬Ôò¿É²ÂÏëËùµÃ¹ÌÌåÎïÖʵijɷ֣¨Ð´ÎïÖʵĻ¯Ñ§Ê½£©£º²ÂÏëÒ»£º2KMnO4¡¢K2MnO4¡¢MnO2£»
²ÂÏë¶þ£ºK2MnO4¡¢MnO2
¢ÚÔÚʵÑéÊÒÓøßÃÌËá¼Ø¼ÓÈÈÒ²ÄܲúÉúÑõÆø£¬Ð¡ºìͬѧ½«16gµÄ¸ßÃÌËá¼Ø·ÅÔÚÊÔ¹ÜÖмÓÈÈÒ»¶Îʱ¼äºó£¬ÀäÈ´£¬³ÆµÃÊ£ÓàÎïÖʵÄÖÊÁ¿Îª14.4g£®Ôò¿ÉÖªÆä²îΪÉú³ÉÑõÆøµÄÖÊÁ¿£¬Îª1.6g£®
½â£ºÉè¸ßÃÌËá¼ØµÄÖÊÁ¿Îªx£®
2KMnO4
K2MnO4+MnO2+O2¡ü
2¡Á158 32
x 1.6g
Ôò
=
£¬½âµÃx=15.8g£¼16g£®
¹Ê¾¹ý¼ÆËãÈ·¶¨²ÂÏë KMnO4¡¢K2MnO4¡¢MnO2ÊÇÕýÈ·µÄ£®
¹Ê´ð°¸Îª£º£¨1£©´ø»ðÐǵÄľÌõ£®£¨2£©³ÎÇåʯ»ÒˮûÓб仯£®£¨3£©0.8kg£»
£¨4£©¢Ù²ÂÏëÒ»£ºKMnO4¡¢K2MnO4¡¢MnO2£»²ÂÏë¶þ£ºK2MnO4¡¢MnO2
¢ÚKMnO4¡¢K2MnO4¡¢MnO2
£¨1£©ÒòΪÑõÆøÄÜÖ§³ÖȼÉÕ£¬¹Ê¿ÉÒÔÓôø»ðÐǵÄľÌõ·ÅÔÚ¼¯ÆøÆ¿¿Ú¼ìÑéÑõÆø£»
£¨2£©Èç¹û³ÎÇåʯ»ÒˮûÓб仯£¬Ôò˵Ã÷¶þÑõ»¯Ì¼Òѱ»¹ýÑõ»¯ÄÆÍêÈ«ÎüÊÕ£®
£¨3£©ÈôÿÈËÿÌì²úÉúµÄ¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª2.2ǧ¿Ë£¬Ôò¸ù¾Ý»¯Ñ§·½³Ìʽ¿ÉÒÔ¼ÆË㣮
½â£ºÉèÀíÂÛÉϿɲúÉúÑõÆøµÄÖÊÁ¿Îªx£¬
2Na2O2+2CO2=2Na2CO3+O2
88 32
2.2kg x
Ôò
88 |
2.2kg |
32 |
x |
´ð£ºÔòÀíÂÛÉϿɲúÉúÑõÆø0.8ǧ¿Ë£®
£¨4£©¢Ù¸ù¾Ý»¯Ñ§·½³Ìʽ2KMnO4
| ||
²ÂÏë¶þ£ºK2MnO4¡¢MnO2
¢ÚÔÚʵÑéÊÒÓøßÃÌËá¼Ø¼ÓÈÈÒ²ÄܲúÉúÑõÆø£¬Ð¡ºìͬѧ½«16gµÄ¸ßÃÌËá¼Ø·ÅÔÚÊÔ¹ÜÖмÓÈÈÒ»¶Îʱ¼äºó£¬ÀäÈ´£¬³ÆµÃÊ£ÓàÎïÖʵÄÖÊÁ¿Îª14.4g£®Ôò¿ÉÖªÆä²îΪÉú³ÉÑõÆøµÄÖÊÁ¿£¬Îª1.6g£®
½â£ºÉè¸ßÃÌËá¼ØµÄÖÊÁ¿Îªx£®
2KMnO4
| ||
2¡Á158 32
x 1.6g
Ôò
2¡Á158 |
x |
32 |
1.6g |
¹Ê¾¹ý¼ÆËãÈ·¶¨²ÂÏë KMnO4¡¢K2MnO4¡¢MnO2ÊÇÕýÈ·µÄ£®
¹Ê´ð°¸Îª£º£¨1£©´ø»ðÐǵÄľÌõ£®£¨2£©³ÎÇåʯ»ÒˮûÓб仯£®£¨3£©0.8kg£»
£¨4£©¢Ù²ÂÏëÒ»£ºKMnO4¡¢K2MnO4¡¢MnO2£»²ÂÏë¶þ£ºK2MnO4¡¢MnO2
¢ÚKMnO4¡¢K2MnO4¡¢MnO2
µãÆÀ£º±¾ÌâΪ¸ù¾Ý»¯Ñ§·½³Ìʽ¼ÆËãÀàÎÊÌâÖеĻù´¡¼ÆË㣬ÍêÕûµÄ¼ÆËã²½Öè¡¢¹æÂɵÄÊéд¸ñʽÊǽâ´ð´ËÀàÎÊÌâʱÐèÒªÁôÒâµÄµØ·½£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿