ÌâÄ¿ÄÚÈÝ

ijÐËȤС×éͬѧ¶ÔʵÑéÊÒÖƱ¸ÑõÆøµÄÌõ¼þ½øÐÐÈçÏÂ̽¾¿ÊµÑé¡£

¢ÙΪ̽¾¿´ß»¯¼ÁµÄÖÖÀà¶ÔË«ÑõË®·Ö½âËٶȵÄÓ°Ï죬¼×Éè¼ÆÒÔ϶ԱÈʵÑ飺

¢ñ£®½«3.0g 10%H2O2ÈÜÒºÓë1.0 g MnO2¾ùÔÈ»ìºÏ

¢ò£®½«x g10% H2O2ÈÜÒºÓë1.0g CuO¾ùÔÈ»ìºÏ

ÔÚÏàͬζÈÏ£¬ ±È½ÏÁ½×éʵÑé²úÉúO2µÄ¿ìÂý¡£

¢ñÖз´Ó¦µÄ»¯Ñ§£¨·ûºÅ£©±í´ïʽÊÇ____¡ø____£»¢òÖÐxµÄֵӦΪ___¡ø_____¡£

¢ÚÒÒ̽¾¿ÁËÓ°ÏìË«ÑõË®·Ö½âËٶȵÄijÖÖÒòËØ¡£ÊµÑéÊý¾Ý¼Ç¼ÈçÏ£º

Ë«ÑõË®µÄÖÊÁ¿

Ë«ÑõË®µÄŨ¶È

MnO2µÄÖÊÁ¿

Ïàͬʱ¼äÄÚ²úÉúO2Ìå»ý

¢ñ

50.0g

1%

0.1g

9 mL

¢ò

50. 0g

2%

0.1g

16 mL

¢ó

50.0g

4%

0.1g

31 mL

        ±¾ÊµÑéÖУ¬²âÁ¿O2Ìå»ýµÄ×°ÖÃÊÇ____¡ø____£¨Ìî±àºÅ£©¡£

ʵÑé½áÂÛ£ºÔÚÏàͬÌõ¼þÏ£¬______¡ø_________£¬Ë«ÑõË®·Ö½âµÃÔ½¿ì¡£

±ûÓÃÓÒͼװÖýøÐÐʵÑ飬ͨ¹ý±È½Ï______¡ø_____Ò²ÄܴﵽʵÑéÄ¿µÄ¡£

¢ÙÂÔ  3.0

¢ÚC  Ë«ÑõˮŨ¶ÈÔ½´ó   Ïàͬʱ¼äÌìƽ¶ÁÊý²îÖµ´óС£¨ÆäËüºÏÀíÒ²¿É£©

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨2012?½­ÄþÇøһģ£©Ä³ÐËȤС×éͬѧ·¢ÏÖʵÑę́ÉÏÕûÆë°Ú·ÅµÄÒ©Æ·ÖУ¨¼ûͼ£©£¬ÓÐÒ»ÊÔ¼ÁÆ¿µÄ±êÇ©ÆÆË𣮠
¡¾Ìá³öÎÊÌâ¡¿ÕâÆ¿ÊÔ¼ÁµÄ³É·ÖÊÇʲô£¿
¡¾Éè¼ÆʵÑé¡¿
£¨1£©Ð¡Ã÷Óýྻ¸ÉÔïµÄ²£Á§°ôպȡ¸ÃÈÜÒºµÎµ½ÊªÈóµÄpHÊÔÖ½ÉÏ£¬²âµÃpH=10£¬ËûÅжÏÕâÊÇÒ»ÖÖ¼îÐÔÈÜÒº£®¶ÔËûµÄ²Ù×÷·½·¨¡¢²âÁ¿½á¹û¼°½áÂÛµÄÆÀ¼Û£¬ÕýÈ·µÄÊÇ
B
B
£»
A£®·½·¨ÕýÈ·£¬½á¹ûÕýÈ·£¬ÇÒ½áÂÛÕýÈ·          B£®·½·¨²»ÕýÈ·£¬½á¹ûƫС£¬µ«½áÂÛÕýÈ·
C£®·½·¨²»ÕýÈ·£¬½á¹ûÆ«´ó£¬½áÂÛ²»ÕýÈ·        D£®·½·¨ÕýÈ·£¬½á¹ûÕýÈ·£¬µ«½áÂÛ²»ÕýÈ·
£¨2£©Ð¡Ã÷ÈÏΪËüÊÇBa£¨OH£©2ÈÜÒº£¬Ð¡¿¡ÈÏΪËüÊÇBa£¨NO3£©2ÈÜÒº£®Òª½øÒ»²½È·¶¨ËüµÄ³É·Ö£¬Ð¡¿¡ÈÏΪֻÐèÑ¡ÔñÉÏͼÒÑÓеÄÊÔ¼Á¾ÍÄÜ°ÑËü¼ø±ð³öÀ´£®ËûÃÇÓÖ½øÐÐÁËʵÑ飮
²Ù×÷²½Öè ʵÑéÏÖÏó ½áÂÛ¼°»¯Ñ§·½³Ìʽ
È¡ÑùµÎÈëÊ¢ÓжþÑõ»¯Ì¼µÄ¼¯ÆøÆ¿ÖÐ
Óа×É«»ë×Ç
Óа×É«»ë×Ç
²ÂÏëÕýÈ·
Ïà¹ØµÄ»¯Ñ§·½³Ìʽ
CO2+Ba£¨OH£©2¨TBaCO3¡ý+H2O
CO2+Ba£¨OH£©2¨TBaCO3¡ý+H2O
¡¾ÖªÊ¶Éý»ª¡¿£¨3£©ÎÒÄÜд³öÆäÖзûºÏÏÂÁÐÌõ¼þµÄ»¯Ñ§·½³Ìʽ£¬
¢ÙÓа×É«³ÁµíµÄÖкͷ´Ó¦£º
H2SO4+Ba£¨OH£©2¨TBaSO4¡ý+2H2O
H2SO4+Ba£¨OH£©2¨TBaSO4¡ý+2H2O
£»
¢ÚÁòËáÍ­ÈÜÒºÓëÇâÑõ»¯±µÈÜÒºÖ®¼ä·´Ó¦£º
CuSO4+Ba£¨OH£©2¨TBaSO4¡ý+Cu£¨OH£©2¡ý
CuSO4+Ba£¨OH£©2¨TBaSO4¡ý+Cu£¨OH£©2¡ý
£®
£¨4£©ÎÒ·¢ÏÖNaOHºÍH2SO4ÈÜÒºÄÜ·¢Éú¸´·Ö½â·´Ó¦£¬ÒòΪÈÜÒºÖеÄH+ºÍOH-²»ÄÜ´óÁ¿¹²´æ£»ÎÒ»¹·¢ÏÖÔÚÈÜÒºÖÐ
Ba2+
Ba2+
ºÍ
SO42-
SO42-
£»
Cu2+
Cu2+
ºÍ
OH-
OH-
£¨ÌîÀë×Ó·ûºÅ£©Ò²²»ÄÜ´óÁ¿¹²´æ£®
ijÐËȤС×éͬѧ¶ÔʵÑéÊÒÖƱ¸ÑõÆøµÄÌõ¼þ£¬¼°ÑõÆøµÄÐÔÖʽøÐÐÈçÏÂ̽¾¿£®
ʵÑéÒ»£ºÎªÌ½¾¿²»Í¬´ß»¯¼Á¶ÔÂÈËá¼Ø·Ö½âËÙÂʵÄÓ°Ï죬¼×Éè¼ÆÒÔ϶ԱÈʵÑ飺
¢ñ£®½«3.0g KClO3Óë1.0g MnO2¾ùÔÈ»ìºÏ¼ÓÈÈ
¢ò£®½«x g KClO3Óë1.0g CuO¾ùÔÈ»ìºÏ¼ÓÈÈ
ÔÚÏàͬζÈÏ£¬±È½ÏÁ½×éʵÑé²úÉúO2µÄ¿ìÂý£®
£¨1£©¢ñÖз´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ
2KClO3
 MnO2 
.
¡÷
2KCl+3O2¡ü
2KClO3
 MnO2 
.
¡÷
2KCl+3O2¡ü
£¬¸Ã·´Ó¦ÀàÐÍΪ
·Ö½â·´Ó¦
·Ö½â·´Ó¦
£»
£¨2£©¢òÖÐxµÄֵӦΪ
3.0
3.0
£®
ʵÑé¶þ£ºÒÒ̽¾¿ÁËÓ°ÏìË«ÑõË®£¨¼´¹ýÑõ»¯ÇâÈÜÒº£©·Ö½âËÙÂʵÄijÖÖÒòËØ£®ÊµÑéÊý¾ÝÈçÏ£º
Ë«ÑõË®µÄÖÊÁ¿ Ë«ÑõË®µÄŨ¶È MnO2µÄÖÊÁ¿ Ïàͬʱ¼äÄÚ²úÉúO2Ìå»ý
¢ñ 50.0g 1% 0.1g 9mL
¢ò 50.0g 2% 0.1g 16mL
¢ó 50.0g 4% 0.1g 31mL
£¨1£©·ÖÎö±íÖÐÊý¾Ý¿ÉÖª£ºÔÚÏàͬÌõ¼þÏ£¬
Ë«ÑõˮŨ¶ÈÔ½´ó
Ë«ÑõˮŨ¶ÈÔ½´ó
£¬Ë«ÑõË®·Ö½âµÃÔ½¿ì£®
£¨2£©Èô²â¶¨ÏàͬÌõ¼þÏÂ
²úÉúÏàͬÌå»ýµÄÑõÆøËùÐèʱ¼ä
²úÉúÏàͬÌå»ýµÄÑõÆøËùÐèʱ¼ä
£¬Ò²¿ÉµÃ³öÏàͬµÄ½áÂÛ£®
ʵÑéÈý£ººÆȻͬѧ×öϸÌúË¿ÔÚÑõÆøÖÐȼÉÕµÄʵÑéʱ£¬Ëû°ÑϸÌúË¿ÈƳÉÂÝÐý×´£¬Ò»¶ËϵÔÚÒ»¸ù´ÖһЩµÄÌúË¿ÉÏ£¬ÁíÒ»¶ËϵÉÏÒ»¸ù»ð²ñ£®µãȼ»ð²ñºó£¬Ñ¸ËÙ°ÑϸÌúË¿Á¬Í¬»ð²ñÒ»Æð²åÈ뼯Æøƿϲ¿£¨Ã»ÓнӴ¥µ½Ï¸É³£¬ÈçͼËùʾ£©£¬µ«²»¼ûÌú˿ȼÉÕ£®Èç´Ë·´¸´Êý´Î£¬ÊµÑé¾ùδ³É¹¦£®
£¨1£©¸Ãͬѧʧ°ÜµÄ¿ÉÄÜÔ­ÒòÊÇ
ÌúË¿ÉúÐâ
ÌúË¿ÉúÐâ
£®¸Ä½øºó£¬ÊµÑé³É¹¦ÁË£®
£¨2£©ÌúË¿ÔÚÑõÆøÖÐȼÉÕµÄÏÖÏóÊÇ
¾çÁÒȼÉÕ£¬»ðÐÇËÄÉ䣬·Å³ö´óÁ¿µÄÈÈ£¬Éú³ÉÒ»ÖÖºÚÉ«¹ÌÌå
¾çÁÒȼÉÕ£¬»ðÐÇËÄÉ䣬·Å³ö´óÁ¿µÄÈÈ£¬Éú³ÉÒ»ÖÖºÚÉ«¹ÌÌå
£»
£¨3£©·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ
3Fe+2O2
 µãȼ 
.
 
Fe3O4
3Fe+2O2
 µãȼ 
.
 
Fe3O4
£»
£¨4£©¼¯ÆøÆ¿ÖÐϸɳµÄ×÷ÓÃ
·ÀÖ¹ÈÛ»¯ÎヲÂäÏÂÀ´£¬Ôì³É¼¯ÆøÆ¿ÆÆÁÑ
·ÀÖ¹ÈÛ»¯ÎヲÂäÏÂÀ´£¬Ôì³É¼¯ÆøÆ¿ÆÆÁÑ
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø