ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿Ä³Æ·ÅÆάCÅÝÌÚƬ±êÇ©Èçͼ1Ëùʾ¡£ÎªÑо¿ÆäÐÔÖʲ¢²â¶¨ÆäÖÐNaHCO3º¬Á¿£¬Éè¼ÆÈçÏÂ̽¾¿¹ý³Ì¡£

£¨1£©Î¬CÅÝÌÚƬÖÐÊôÓÚÓлúÎïµÄÓгÈζÏãÁÏ¡¢ÄûÃÊËá¡¢_______¡£

£¨2£©½«Î¬CÅÝÌÚƬͶÈëË®ÖУ¬¹Û²ìµ½ÓдóÁ¿ÆøÅݲúÉú£¬Ö÷ÒªÊÇÒòΪÄûÃÊËᣨH3C6H5O7£©ºÍNaHCO3·¢Éú·´Ó¦£¬ÇëÍêÉƸ÷´Ó¦£º

3NaHCO3+H3C6H5O7= Na3C6H5O7+3 H2O+_______¡£

£¨3£©Îª²â¶¨NaHCO3º¬Á¿£¬Éè¼Æͼ2×°Ö㬲¢°´ÏÂÊö²½Öè²Ù×÷¡£

ʵÑé²½Ö裺³ÆÈ¡ÑùÆ·m g×°Ìîµ½½ºÄÒÖУ¬ÔÚСÊÔ¹ÜÖзÅÈëСÐÍ´ÅÁ¦½Á°è×Ó£¬ÔÙ¼ÓÈë×ãÁ¿Ï¡ÑÎËᣬÔٰѽºÄҷŵ½ÊÔ¹ÜÖУ»ÔÚ500 mLÏ´Æ¿ÄÚ×°ÈëÒ»¶¨Á¿µÄ±¥ºÍ̼ËáÇâÄÆÈÜÒº£»°ÑСÊÔ¹ÜСÐÄ·ÅÈëÏ´Æ¿£¨Èçͼ2£©£¬¸ÇºÃÏ´Æ¿µÄ¸Ç×Ó£¬·ÅÔÚ´ÅÁ¦½Á°èÆ÷ÉÏ£»½ºÄÒÈܽ⣬ÅÝÌÚƬÓëÑÎËá×÷Ó㬷´Ó¦½Ó½üÍê³É£¬´ò¿ª½Á°èÆ÷£¬Ö±ÖÁÏ´Æ¿ÄÚÎÞÒºÌåÁ÷³ö£¬ÓÃÁ¿Í²½ÓÈ¡Ï´Æ¿ÄÚÁ÷³öµÄÒºÌå¶ÁÊýΪV mL¡£Ê¹ÓýºÄÒµÄÄ¿µÄÊÇ_______£¬½Á°è×ÓµÄ×÷ÓÃÊÇ_______£¬±¥ºÍ̼ËáÇâÄÆ´úÌæË®£¬¿ÉÒÔ·ÀÖ¹_______¡£ÒÑÖª¸ÃζÈÏÂCO2ÃܶÈÊÇ¦Ñ g/mL£¬ÔòάCÅÝÌÚƬÖÐNaHCO3º¬Á¿ÊÇ_______¡£

£¨4£©ÏÂÁвÙ×÷¿ÉÄܵ¼Ö²ⶨ½á¹ûƫСµÄÊÇ_______¡£

a£®Ð¡ÊÔ¹ÜÖÐÑÎËáÒç³öµ½Ï´Æ¿ÄÚ b£®ÊµÑé½áÊø£¬ÑöÊÓÁ¿Í²¶ÁÊý

c£®³ÆÁ¿m gάCÅÝÌÚƬʱ£¬ÆäËû²Ù×÷¾ùÕýÈ·£¬×îÖÕÌìƽָÕëÆ«×ó¼´½áÊø³ÆÁ¿

d£®Î¬CÅÝÌÚƬÔÚ×°Ìîµ½½ºÄÒÖÐʱÉÙÁ¿Èö³ö

£¨5£©Ä³Í¬Ñ§Éè¼Æ×°Öã¨Èçͼ3£©²â¶¨NaHCO3º¬Á¿¡£ÊµÏÖÑùÆ·ÓëÏ¡ÁòËá·´Ó¦µÄ²Ù×÷ÊÇ_______£¬

Óû²â¶¨NaHCO3º¬Á¿ÐèÒªµÄÊý¾Ý×éºÏÓÐ_______¡¢_______¡£

a£®ÑùÆ·ÖÊÁ¿m g

b£®·´Ó¦Ç°ºóA×°ÖÃÖÊÁ¿a g¡¢a1 g

c£®·´Ó¦Ç°ºóB×°ÖÃÖÊÁ¿b g¡¢b1 g

d£®·´Ó¦Ç°ºóC×°ÖÃÖÊÁ¿c g¡¢c1 g

ÇëÑ¡ÔñÆäÖÐÒ»×éÊý¾Ý£¬±íʾNaHCO3º¬Á¿_______¡£Ö¸³ö¸Ã×°ÖõÄÒ»¸öȱÏÝÊÇ_______¡£

¡¾´ð°¸¡¿ ÕáÌǺÍάÉúËØC 3CO2 ·ÀֹάCÅÝÌÚƬÖÐNaHCO3¹ýÔçÓëËá·´Ó¦µ¼ÖÂCO2Òݳö ʹ·´Ó¦³ä·Ö CO2Èܽâ 21¦Ñv/11m bd ½«YÐ͹ÜÂÔÏò×óÇãб£¬Ê¹ÁòËáÁ÷ÈëÑùÆ·Ò»¶Ë ab ¡¾´ðÌâ¿Õ10¡¿ac »ò Éú³ÉµÄ¶þÑõ»¯Ì¼Î´ÄÜÍêÈ«Åųö»òδÄܱ»NaOHÍêÈ«ÎüÊÕ

¡¾½âÎö¡¿ÓÉÌâÖÐÐÅÏ¢Öª£¬£¨1£©Î¬CÅÝÌÚƬÖÐÊôÓÚÓлúÎïµÄÓгÈζÏãÁÏ¡¢ÄûÃÊËá¡¢ÕáÌǺÍάÉúËØC¡££¨2£©½«Î¬CÅÝÌÚƬͶÈëË®ÖУ¬¹Û²ìµ½ÓдóÁ¿ÆøÅݲúÉú£¬Ö÷ÒªÊÇÒòΪÄûÃÊËᣨH3C6H5O7£©ºÍNaHCO3·¢Éú·´Ó¦£¬¸Ã·´Ó¦£º3NaHCO3+H3C6H5O7= Na3C6H5O7+3H2O+ 3CO2 ¡ü¡££¨3£©²â¶¨NaHCO3º¬Á¿¡£Ê¹ÓýºÄÒµÄÄ¿µÄÊÇ. ·ÀֹάCÅÝÌÚƬÖÐNaHCO3¹ýÔçÓëËá·´Ó¦µ¼ÖÂCO2Òݳö¡£½Á°è×ÓµÄ×÷ÓÃÊÇʹ·´Ó¦³ä·Ö¡£±¥ºÍ̼ËáÇâÄÆ´úÌæË®£¬¿ÉÒÔ·ÀÖ¹CO2Èܽ⡣ÒÑÖª¸ÃζÈÏÂCO2ÃܶÈÊÇ¦Ñ g/mL£¬ÔòάCÅÝÌÚƬÖÐNaHCO3º¬Á¿ÊÇ¡ÃÉú³É¶þÑõ»¯Ì¼ÖÊÁ¿ÊǦÑvg. NaHCO3¡úCO2,, £½ ,x£½21¦Ñv/11g. £¨4£©²Ù×÷¿ÉÄܵ¼Ö²ⶨ½á¹ûƫСµÄÊÇb£®ÊµÑé½áÊø£¬ÑöÊÓÁ¿Í²¶ÁÊý. d£®Î¬CÅÝÌÚƬÔÚ×°Ìîµ½½ºÄÒÖÐʱÉÙÁ¿Èö³ö. £¨5£©²â¶¨NaHCO3º¬Á¿¡£ÊµÏÖÑùÆ·ÓëÏ¡ÁòËá·´Ó¦µÄ²Ù×÷Êǽ«YÐ͹ÜÂÔÏò×óÇãб£¬Ê¹ÁòËáÁ÷ÈëÑùÆ·Ò»¶Ë¡£Óû²â¶¨NaHCO3º¬Á¿ÐèÒªµÄÊý¾Ý×éºÏÓÐa£®ÑùÆ·ÖÊÁ¿m g£¬b£®·´Ó¦Ç°ºóA×°ÖÃÖÊÁ¿a g¡¢a1 g¡£a£®ÑùÆ·ÖÊÁ¿m g£¬c£®·´Ó¦Ç°ºóB×°ÖÃÖÊÁ¿b g¡¢b1 g¡£ÇëÑ¡ÔñÆäÖÐÒ»×éÊý¾Ý£¬±íʾNaHCO3º¬Á¿ÊÇ »ò £¬Éú³ÉµÄ¶þÑõ»¯Ì¼Î´ÄÜÍêÈ«Åųö»òδÄܱ»NaOHÍêÈ«ÎüÊÕ¡£

¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿ÎªÁ˲ⶨÑùÆ·CaSO4XH2OºÍCaCO3»ìºÏÎïµÄ×é³É£¬ÊµÑéС×éÀûÓÃÏÂͼËùʾµÄ×°Ö㨼гÖÒÇÆ÷Ê¡ÂÔ£©½øÐÐʵÑé¡£

£¨1£©ÊµÑéÇ°Ê×ÏÈÒª_________£¬ÔÙ×°ÈëÑùÆ·¡£×°ÖÃAÖмîʯ»ÒµÄ×÷ÓÃÊÇ___________¡£

£¨2£©C×°ÖõÄ×÷ÓÃÊÇÓ¦ÓÃÁËŨÁòËá¾ßÓÐ___________µÄÐÔÖÊ¡£

£¨3£©ÒÑÖªCaSO4XH2Oʧȥȫ²¿½á¾§Ë®µÄζÈΪ160¡æ£¬1350¡æʱCaSO4¿ªÊ¼·Ö½â£»CaCO3ÔÚ900¡æʱ·Ö½âÍêÈ«¡£ÏÖ¿ØÖÆB×°ÖÃζÈ900¡æ½øÐÐʵÑ飬²¢²É¼¯ÁËÈçÏÂʵÑéÊý¾Ý£º

a£®ÑùÆ·µÄÖÊÁ¿Îªm1g b£®·´Ó¦ºó²£Á§¹ÜÖйÌÌåµÄÖÊÁ¿Îªm2g

c£®×°ÖÃCʵÑéºóÔöÖØm3g d£®×°ÖÃDʵÑéºóÔöÖØm4g

ÈôʵÑé²âµÃm1=22.20 g£¬m3=3.60 g£¬m4=2.20 g¡£

Ç󣺢ÙÑùÆ·ÖÐCaCO3µÄÖÊÁ¿___________ g£»¢ÚXµÄÖµ_____________¡£

£¨4£©×°ÖÃEµÄ×÷ÓÃÊÇ_________£¬ÈôȱÉÙE×°Ö㬲âµÃCaCO3µÄÖÊÁ¿___________£¨Ñ¡Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±¡¢¡°²»±ä¡±£©£¬XµÄÖµ»á___________£¨Ñ¡Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±¡¢¡°²»±ä¡±£©¡£

£¨5£©ÄãÈÏΪ»¹¿ÉÑ¡ÓÃÏÂÁÐ_________£¨Ñ¡ÌîÐòºÅ£©Êý¾Ý×éºÏÒ²¿ÉÇó³öXµÄÖµ¡£

A£®ab B£®abd C£®bcd

£¨6£©CaSO4µ±Î¶ȴﵽ1350¡æʱ·Ö½â»á²úÉúÒ»ÖÖ¹ÌÌåÑõ»¯ÎïÓëÁ½ÖÖÆøÌ壬ÆäÖÐÒ»ÖÖÆøÌåÓд̼¤ÐÔÆø棬Æä·Ö½âµÄ»¯Ñ§·½³ÌʽΪ___________¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø