ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÓÐÒ»°ü¹ÌÌå·ÛÄ©£¬¿ÉÄܺ¬ÓÐþ·Û¡¢Ì¼·Û¡¢Ñõ»¯Í¡¢ÁòËá¼Ø¡¢ÇâÑõ»¯ÄÆÖеÄÒ»ÖÖ»ò¼¸ÖÖ¡£ÎªÌ½¾¿¹ÌÌåµÄ×é³É£¬Ä³»¯Ñ§ÐËȤС×é½øÐÐÈçͼËùʾµÄʵÑ飺
»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÊµÑéÖÐÉú³É°×É«ÂËÔüÒҵĻ¯Ñ§·½³ÌʽÊÇ__________¡£
£¨2£©Ô¹ÌÌåÖÐÒ»¶¨Ã»ÓеÄÎïÖÊÊÇ___________£¨Ìѧʽ£©¡£
£¨3£©ÊµÑé½áÊøºó£¬¸ÃС×齫ÂËÒºCºÍÂËÒºD¶¼µ¹Èë·ÏÒº¸×£¬Óа×É«³ÁµíÉú³É£¬ÔòÂËÒºCÖÐÒ»¶¨º¬ÓеÄÑôÀë×ÓÓÐ________¡££¨ÌîÀë×Ó·ûºÅ£©
£¨4£©Èç¹ûÂËÔü±ûµÄÖÊÁ¿µÈÓÚ¹ÌÌå²ÐÁôÎﶡµÄÖÊÁ¿£¬ÔòÆøÌåFÓë¹ÌÌå²ÐÁôÎﶡµÄÖÊÁ¿±ÈΪ_____¡£
¡¾´ð°¸¡¿K2SO4+Ba(NO3)2=BaSO4¡ý+2KNO3 NaOH Ba2+¡¢Cu2+¡¢K+ 11:15
¡¾½âÎö¡¿
Ñõ»¯Í¡¢Ã¾·Û¡¢Ì¼·Û¶¼²»ÈÜÓÚË®£¬Ì¼·Û²»ÈÜÓÚËᣬÇâÑõ»¯ÄƺÍÏõËáÍ»áÉú³ÉÇâÑõ»¯Í³Áµí£¬ÁòËá¼ØºÍÏõËá±µ»áÉú³ÉÁòËá³ÁµíµÈ֪ʶ½øÐзÖÎö¡£
£¨1£©Éú³É°×É«³ÁµíÂËÔüÒҵķ´Ó¦ÊÇÁòËá¼ØºÍÏõËá±µ·´Ó¦Éú³ÉÁòËá±µ³ÁµíºÍÏõËá¼Ø£¬»¯Ñ§·½³ÌʽΪ£ºK2SO4+Ba(NO3)2==BaSO4¡ý+2KNO3£»¹ÊÌK2SO4+Ba(NO3)2==BaSO4¡ý+2KNO3
£¨2£©Í¨¹ýÍƵ¼¿ÉÖª£¬Ô¹ÌÌåÖÐÒ»¶¨²»º¬ÓеÄÎïÖÊÊÇÇâÑõ»¯ÄÆ£¬ÔÒòÊÇ£ºÂËÒºAÖмÓÈë¹ýÁ¿µÄÏõËáÍÈÜÒº£¬ÎÞÃ÷ÏÔÏÖÏó£»¹ÊÌÇâÑõ»¯ÄÆ
£¨3£©ÂËÒºCÖеÄÈÜÖÊÓÐCu(NO3)2£¬Ba(NO3)2ºÍKNO3£¬ÈÜÒºÖк¬ÓеÄÑôÀë×ÓΪ£ºBa2+¡¢Cu2+¡¢K+£»¹ÊÌBa2+¡¢Cu2+¡¢K+
£¨4£©ÂËÔü±ûÊÇ̼ºÍÍ£¬¹ÌÌå²ÐÁôÎﶡÊÇÑõ»¯Í£¬¶þÕßÖÊÁ¿ÏàµÈ£¬ËµÃ÷ÂËÔü±ûÖÐ̼ԪËصÄÖÊÁ¿µÈÓÚÑõ»¯ÍÖÐÑõÔªËصÄÖÊÁ¿£¬ÈôÑõ»¯ÍµÄÖÊÁ¿Îª80£¬Ôò̼ԪËصÄÖÊÁ¿Îª16£¬Éú³É¶þÑõ»¯Ì¼µÄÖÊÁ¿Îª£¬¹Ê¶þÑõ»¯Ì¼ºÍÑõ»¯ÍµÄÖÊÁ¿±ÈΪ£º£¬¹ÊÌ11£º15
¡¾ÌâÄ¿¡¿ÈÜÒºÓëÈËÃǵÄÉú»îϢϢÏà¹Ø¡£
£¨1£©ÏÂÁÐÉÙÁ¿ÎïÖÊ·Ö±ð·ÅÈëË®ÖУ¬³ä·Ö½Á°è£¬¿ÉÒԵõ½ÈÜÒºµÄÊÇ_____£¨Ìî×Öĸ£©¡£
A ¸ßÃÌËá¼Ø B ÆûÓÍ C Ãæ·Û D µâµ¥ÖÊ
£¨2£©ÇâÑõ»¯ÄÆ¡¢Ì¼ËáÄÆ·Ö±ðÔÚË®¡¢¾Æ¾«ÖеÄÈܽâ¶ÈÈç±íËùʾ
ÇâÑõ»¯ÄÆ | ̼ËáÄÆ | ||||
20¡æ | 40¡æ | 20¡æ | 40¡æ | ||
Ë® | 109g | 129g | 21.8g | 49g | |
¾Æ¾« | 17.3g | 40g | ²»ÈÜ | ²»ÈÜ |
¢ÙÉÏÊöͼÏó±íʾ_____£¨Ìî¡°ÇâÑõ»¯ÄÆ¡±»ò¡°Ì¼ËáÄÆ¡±£©µÄÈܽâ¶ÈÇúÏß¡£
¢Ú20¡æʱ£¬ÇâÑõ»¯ÄƵÄÈܽâ¶È_____£¨Ìî¡°´óÓÚ¡±»ò¡°Ð¡ÓÚ¡±£©Ì¼ËáÄƵÄÈܽâ¶È¡£
¢Û40¡æʱ£¬·Ö±ð½«50gNaOH·Ö±ðͶÈëµ½100gË®ºÍ100g¾Æ¾«ÖУ¬ÄÜÐγɱ¥ºÍÈÜÒºµÄÊÇ_____£¨Ñ¡Ìî¡°Ë®¡±»ò¡°¾Æ¾«¡±£©£¬ÔÙ½«ÊÊÁ¿CO2ͨÈëËùµÃNaOHµÄ¾Æ¾«ÈÜÒºÖУ¬¹Û²ìµ½µÄÏÖÏóΪ_____£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£º_____¡£