ÌâÄ¿ÄÚÈÝ

Óú¬ÓжþÑõ»¯Ì¼ºÍË®ÕôÆøÔÓÖʵÄijÖÖ»¹Ô­ÐÔÆøÌå²â¶¨Ò»ÖÖÌúµÄÑõ»¯ÎFexOy£©µÄ×é³É£¬ÊµÑé×°ÖÃÈçͼËùʾ£®
¾«Ó¢¼Ò½ÌÍø
¸ù¾ÝÉÏͼÊԻشð£º
£¨1£©¼××°ÖõÄ×÷ÓÃÊÇ
 
£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ
 
£®
£¨2£©ÊµÑé¹ý³ÌÖж¡×°ÖÃûÓÐÃ÷ÏԱ仯£¬¶øÎì×°ÖÃÖÐÈÜÒº³öÏÖÁË°×É«³Áµí£¬Ôò¸Ã»¹Ô­ÐÔÆøÌåÊÇ
 
£®
£¨3£©µ±±û×°ÖÃÖеÄFexOy£¬È«²¿±»»¹Ô­ºó£¬³ÆÁ¿Ê£Óà¹ÌÌåµÄÖÊÁ¿Îª16.8g£¬Í¬Ê±²âµÃÎì×°ÖõÄÖÊÁ¿Ôö¼ÓÁË17.6g£®Ôò¸ÃÌúµÄÑõ»¯ÎïµÄ»¯Ñ§Ê½Îª
 
£®
£¨4£©ÉÏÊöʵÑé×°ÖÃÖУ¬Èç¹ûûÓм××°Ö㬽«Ê¹²â¶¨½á¹ûÖÐÌúÔªËØÓëÑõÔªËصÄÖÊÁ¿µÄ±ÈÖµ
 
£»£¨Ìî¡°Æ«´ó¡±¡¢¡°Æ«Ð¡¡±»ò¡°ÎÞÓ°Ï족£©Èç¹ûûÓÐ×îºóµÄ¼º×°Ö㬿ÉÄܲúÉúµÄºó¹ûÊÇ
 
£®
·ÖÎö£º×÷Ϊ×ÛºÏʵÑéÌâÀûÓû¹Ô­ÐÔÆøÌå²â¶¨ÌúµÄÑõ»¯ÎïµÄ×é³É£¬ÆäÔ­ÀíÊǸù¾ÝÉú³ÉÎïµÄÖÊÁ¿Í¨¹ý¼ÆËãÈ·¶¨½á¹û£®¾Í³õÖн׶Σ¬»¹Ô­ÐÔÆøÌåÓÐÇâÆøºÍÒ»Ñõ»¯Ì¼£¬ËûÃǶáÑõºóÉú³ÉË®ºÍ¶þÑõ»¯Ì¼£®Ô­ÆøÌåÖлìÓжþÑõ»¯Ì¼ºÍË®ÕôÆø£¬ËùÒÔ±ØÐëÏȳýÈ¥£¬È»ºóÈû¹Ô­ÐÔÆøÌå·´Ó¦£¬¶¡Îì×°ÖÃÓÃÒÔ¼ìÑéÉú³ÉµÄË®ºÍ¶þÑõ»¯Ì¼£¬×îºóµÄ¼º×°ÖýøÐÐβÆø´¦Àí£¬Óл·±£ÀíÄ
½â´ð£º½â£º£¨1£©Òò¶þÑõ»¯Ì¼ÄÜÓëÇâÑõ»¯ÄÆ·´Ó¦£¬·½³ÌʽΪ£º2NaOH+CO2¨TNa2CO3+H2O£¬ËùÒÔ³ý¶þÑõ»¯Ì¼ÓÃÇâÑõ»¯ÄÆÈÜÒº£¬ÒòŨÁòËá¾ßÓÐÎüË®ÐÔ£¬ËùÒÔ³ýË®ÕôÆøÑ¡ÓÃŨÁòËᣮ³ý¶þÑõ»¯Ì¼Ê±£¬ÆøÌåÒª´ÓÈÜÒºÖÐͨ¹ý£¬»á´ø³öË®ÕôÆø£¬ËùÒÔÒªÏȳý¶þÑõ»¯Ì¼ÔÙ¸ÉÔ˵ÒÔ¼××°ÖõÄ×÷ÓÃÊdzýÈ¥£¨»òÎüÊÕ£©¶þÑõ»¯Ì¼£®
£¨2£©¶¡×°ÖÃÊ¢·ÅµÄÊÇÎÞË®ÁòËáÍ­£¬ÎÞË®ÁòËáÍ­ÓöË®»á±äÀ¶£¬¶¡×°ÖÃûÓÐÃ÷ÏԱ仯£¬ËµÃ÷ûÓÐË®Éú³É£¬¹Ê¸Ã»¹Ô­ÐÔÆøÌå²»ÊÇÇâÆø£®Îì×°ÖÃÊ¢·ÅµÄÊÇʯ»ÒË®£¬¶þÑõ»¯Ì¼ÄÜʹʯ»ÒË®±ä»ë×Ç£¬Îì×°ÖÃÖÐÈÜÒº³öÏÖÁË°×É«³Áµí£¬¹Ê¸Ã»¹Ô­ÐÔÆøÌåÊÇÒ»Ñõ»¯Ì¼£®
£¨3£©±û×°ÖÃÖеÄFexOyÈ«²¿±»»¹Ô­£¬Ê£Óà¹ÌÌåΪÉú³ÉµÄÌúµÄÖÊÁ¿£®Îì×°ÖÃÖÐÊ¢·ÅµÄʯ»ÒË®ÎüË®¶þÑõ»¯Ì¼£¬Ôö¼ÓµÄÖÊÁ¿Îª¶þÑõ»¯Ì¼µÄÖÊÁ¿£®       
YCO+FeXOY
 ¸ßΠ
.
 
XFe+YCO2
                  56X  44Y
                16.8g   17.6g
 
56x
44y
=
16.8g
17.6g
          ½âµÃ£º
X
Y
=
3
4

ËùÒÔ¸ÃÌúµÄÑõ»¯ÎïµÄ×é³ÉΪ£ºFe3O4
£¨4£©Èç¹ûûÓм××°Ö㬻ìÓеĶþÑõ»¯Ì¼Ò²»áÔÚÎì×°Öñ»ÎüÊÕ£¬¹Ê¶þÑõ»¯Ì¼µÄÖÊÁ¿Æ«´ó£¬Ï൱ÓÚÒ»Ñõ»¯Ì¼¶áµÃµÄÑõµÄÖÊÁ¿Ôö¼Ó£¬¹Ê²âµÃ½á¹ûÖÐÌúÔªËØÓëÑõÔªËصÄÖÊÁ¿µÄ±ÈֵƫС£®Ò»Ñõ»¯Ì¼Óж¾£¬»áÎÛȾ¿ÕÆø£¬×îºóµÄ¼º×°ÖöÔβÆø½øÐд¦Àí£¬¾ßÓл·±£ÀíÄ
¹Ê¸ÃÌâµÄ´ð°¸Îª£º
£¨1£©ÎüÊÕCO2£¬2NaOH+CO2¨TNa2CO3+H2O
£¨2£©CO£¨»òÒ»Ñõ»¯Ì¼£©
£¨3£©Fe3O4
£¨4£©Æ«Ð¡£¬Óж¾µÄÒ»Ñõ»¯Ì¼»áÎÛȾ¿ÕÆø£®
µãÆÀ£º¸ÃʵÑéµÄÄ¿µÄÊÇÓû¹Ô­ÐÔÆøÌå²â¶¨ÌúµÄÑõ»¯ÎïµÄ×é³É£¬½â´ðµÄ¹Ø¼üÊÇ·ÖÎöʵÑé×°Öã¬Á˽âÿһ²½µÄ×÷Óã®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
¾«Ó¢¼Ò½ÌÍøijУͬѧ¶ÔÊг¡ÉϵÄʳƷÊèËɼÁ½øÐÐÁËÈçÏÂ̽¾¿£®
ʵÑéÒ»£º¼×С×éµÄͬѧÊÕ¼¯µ½Ò»°üÖ÷Òª³É·ÖÊÇСËÕ´ò£¨Ì¼ËáÇâÄÆ£©µÄÊèËɼÁ
£¨1£©È¡ÑùÆ·ÈÜÓÚÊÊÁ¿µÄË®ÖУ¬²âµÃÈÜÒºµÄpH´óÓÚ7£®
£¨2£©ÏòСËÕ´òÑùÆ·ÖеμÓÑÎËᣬÓдóÁ¿ÆøÅݲúÉú£¬¾­¼ìÑé¸ÃÆøÌåÊǶþÑõ»¯Ì¼£®¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ
 
£®
£¨3£©Í¬Ñ§ÃÇͨ¹ý²éÔÄ×ÊÁÏ£¬ÔÚÀÏʦµÄÖ¸µ¼Ï²ÉÓÃÁËÈçͼËùʾװÖÃÓÃСËÕ´òºÍ´¿¼î×öÁ˶ԱÈʵÑ飮ʵÑéÖÐСÊÔ¹ÜÄÚÕ´ÓÐÎÞË®ÁòËáÍ­·ÛÄ©µÄÃÞ»¨Çò±ä³ÉÀ¶É«£¬aÉÕ±­ÖÐʯ»ÒË®ÎÞÃ÷ÏÔÏÖÏó£¬
bÉÕ±­ÖÐʯ»ÒË®ÁËÏÖ°×É«»ë×Ç£®ÊԻش𣺢ÙÔÚʵÑé½áÊøʱ£¬²Ù×÷ÉÏҪעÒâµÄÎÊÌâÊÇ£º
 

¢ÚÓÉʵÑ飨3£©¿ÉÒԵóöµÄ½áÂÛÊÇ
 
£®±±·½Å©´åµØÇøÓá°¼îÃ桱£¨Ì¼ËáÄÆ£©ÕôÂøͷʱ£¬±ØÐëÏȽ«Ãæ·Û·¢½Í£¨²úÉúһЩÓлúËᣩµÄÔ­ÒòÊÇ
 
£®
ʵÑé¶þ£ºÒÒС×éµÄͬѧÊÕ¼¯µ½Ò»°üÃûΪ¡°³ô·Û¡±µÄÊèËɼÁ£¬ÎªÌ½¾¿Æä×é³É£¬½øÐÐʵÑ飺
£¨1£©¡°³ô·Û¡±ÎªÒ»ÖÖ°×É«¹ÌÌ壬Ò×ÈÜÓÚË®£»
£¨2£©È¡ÉÙÁ¿ÑùÆ·ÓëÏ¡ÑÎËá»ìºÏºó²úÉúÁË¿ÉÒÔʹʯ»ÒË®±ä»ì×ǵÄÆøÌ壻
£¨3£©È¡ÉÙÁ¿ÑùÆ·¼ÓÈȺ󣬲úÉúÁËÓд̼¤ÐÔÆøζµÄÆøÌ壻
£¨4£©ÉÙÁ¿ÑùÆ·ÓëÇâÑõ»¯ÄÆÈÜÒº»ìºÏºó¹²ÈÈ£¬²úÉúÁËʹʪÈóµÄºìɫʯÈïÊÔÖ½±äÀ¶µÄ³ôÆø£®
µ÷²éºóµÃÖª£¬¡°³ô·Û¡±µÄÖ÷Òª³É·ÖÊdzõÖл¯Ñ§¿Î±¾ÖÐÒ»ÖÖ³£¼ûµÄÑΣ®
¢ÙÄãÈÏΪ¸ÃÑÎÊÇ
 
£¬Ëü¼ÓÈȺó·´Ó¦µÄ·½³ÌʽΪ
 

¢ÚÓá°³ô·Û¡±×÷ÊèËɼÁµÄÓÍըʳƷ·ÅÖúóÔÙÏúÊÛºÍʳÓõÄÔ­Òò¿ÉÄÜÊÇ
 
£®
¢ÛijЩСÉÌ··Ï²»¶Ñ¡Óá°³ô·Û¡±´úÌ桰СËÕ´ò¡±×÷ÊèËɼÁµÄÔ­Òò¿ÉÄÜÊÇ
 
£®
ʵÑéÈý£º±ûС×éͬѧ̽¾¿Ð¡ËÕ´ò¡¢¡°³ô·Û¡±ÔÚÖÆ×÷ʳƷ¹ý³ÌÖвúÉúÆøÅݵÄÔ­Òò
£¨1£©Á½ÖÖÊèËɼÁ²úÉúµÄÆøÌåÖж¼º¬ÓÐ
 
£®ÍƲâ²úÉúÕâÖÖÆøÌåµÄÔ­ÒòÓÐ
 
£»
 
£®
£¨2£©Ð¡×éµÄͬѧ½«ÉÙÐíÃæ·Û¼ÓÈëË®ÖÐÈ¡ÉϲãÒºÌåÓÃpHÊÔÖ½²âµÃ£ºpH=7£®²Â²â²úÉúÆøÌåµÄÔ­ÒòÊÇ
 
£®
ʵÑéËÄ£º¶¡Ð¡×éµÄͬѧÔÚij³¬Êз¢ÏÖÒ»ÖÖ¸´ºÏÊèËɼÁ--·¢½Í·Û£¬Æä³É·Ö¼û±í£º
³É·Ö ËùÓÃÎïÖÊ
̼ËáÑÎÀà ̼ËáÇâÄÆ
ËáÐÔÎïÖÊ ÄûÃÊËá¡¢¾ÆʯËáµÈ
ÊèËɼÁ Ã÷·¯
ÆäËû³É·Ö µí·Û¡¢Ö¬·¾ËáµÈ
£¨1£©ÕâÖÖÊèËɼÁ²úÉúµÄÆøÌåÖ÷ÒªÊÇ
 
£»²úÉúÕâÖÖÆøÌåµÄÔ­ÒòÊÇ
 
ºÍ
 
£®
£¨2£©Îª²â¶¨ÆäÖÐ̼ËáÇâÄƵÄÖÊÁ¿·ÖÊý£¬Ð¡×éµÄͬѧÉè¼ÆÁËÈçÏÂʵÑ飬ÆäÖ÷ҪʵÑé²½ÖèÈçÏ£º
¢ñ£®°´Í¼×é×°ÒÇÆ÷£¬½«50.0gÊÔÑù·ÅÈë׶ÐÎÆ¿ÖУ¬¼ÓÈë×ãÁ¿Ä³ËáÈÜÒº£»
¢ò£®²âÁ¿Ò»¶¨Ê±¼äÄÚ¸ÉÔï¹ÜÄÚÎïÖÊÔö¼ÓµÄÖÊÁ¿£¨¼ûÏÂÁÐÇúÏߣ©£»
¢ó£®´ý׶ÐÎÆ¿Öв»ÔÙ²úÉúÆøÅÝʱ£¬´ò¿ª»îÈûB£¬´Óµ¼¹ÜA´¦»º»º¹ÄÈëÒ»¶¨Á¿µÄ¿ÕÆø£»
¢ô£®ÔٴγÆÁ¿¸ÉÔï¹ÜÄÚÎïÖÊÔö¼ÓµÄÖÊÁ¿£»
¢õ£®Öظ´¢óºÍ¢ôµÄ²Ù×÷£¬Ö±ÖÁ¸ÉÔï¹ÜÄÚÎïÖÊÖÊÁ¿²»±ä£®

¾«Ó¢¼Ò½ÌÍø
ÌÖÂÛ£º
¢Ù²½Öè¢ñ£®¼ÓÈëÑùÆ·Ç°»¹Ó¦¼ì²é
 
£¬Ëù¼ÓµÄËáÈÜÒºÊÇ
 
£®
¢Ú×°ÖÃÒÒµÄ×÷ÓÃÊÇ
 
£»´Óµ¼¹ÜA´¦»º»º¹ÄÈëÒ»¶¨Á¿µÄ¿ÕÆøʱ£¬×°Öü׵Ä×÷ÓÃÊÇ
 
£®
¢ÛÇëÀûÓÃÓйØÊý¾Ý¼ÆËãÊÔÑùÖÐ̼ËáÇâÄƵÄÖÊÁ¿·ÖÊý£®£¨Ð´³ö¼ÆËã¹ý³Ì£¬±¾Ð¡Ìâ4·Ö£©
¾«Ó¢¼Ò½ÌÍø°²¶à·òÊÇÒ»ÖÖÄÛÈâ·Û£¬ÆäÖ÷Òª³É·Ö̼ËáÇâÄÆ£¨NaHCO3£©¿ÉÆÆ»µÈâÖÊÏËά½á¹¹¡¢´Ù½øÈâÀàÎüÊÕË®·Ö£¬´Ó¶øʹÈâÖÊËÉÈí£¬´ïµ½ÏÊÄÛˬ»¬µÄÄ¿µÄ£®Ð¡Çà·¢ÏÖ½«°èÁË°²¶à·ò·ÛµÄÈâÀà·Åµ½¹øÖв¢¼ÓÈëʳ´×µÈµ÷ÁÏÉÕÖóʱ²úÉúÁË´óÁ¿ÆøÌ壬Ëû¶Ô´ËÆĸÐÐËȤ£¬¾ö¶¨¶ÔÆä½øÐÐ̽¾¿£®
¢ñ£®Ð¡ÓÚ¶ÔÆøÌåµÄ³É·Ö½øÐÐÁ˲²⣺ÆøÌåÖгýÁË´×ËáÆøÌåÖ®Í⣬»¹¿ÉÄܺ¬ÓÐË®ÕôÆøºÍCO2£®ËûÉè·¨ÊÕ¼¯ÆøÌåÑùÆ·²¢³ýÈ¥´×ËáÆøÌåºó£¬ÓÃÓÒͼʵÑé×°ÖýøÐÐ̽¾¿£®£¨ÆøÌåÒÀ´Îͨ¹ýA¡¢BÁ½ÊÔ¼ÁÆ¿£¬ÒÑ֪ŨÁòËá¾ßÓÐÎüË®ÐÔ£©
ʵÑéÏÖÏó£ºAÆ¿ÖÊÁ¿Ôö¼Ó¡¢BÆ¿ÖÐÓа×É«»ë×ÇÎï²úÉú£®
ʵÑé½áÂÛ£º¸ÃÆøÌåÖÐÒ»¶¨º¬ÓÐ
 
£»
¢ò£®Ð¡ÓÚ¶Ô¶þÑõ»¯Ì¼µÄÀ´Ô´×÷ÁËÁ½Öֲ²⣺
²Â²â¢Ù£º
 
£»
²Â²â¢Ú£º¶þÑõ»¯Ì¼¿ÉÄÜÊÇÓÉ̼ËáÇâÄÆÊÜÈÈ·Ö½â²úÉúµÄ£®
Õë¶ÔÒÔÉϲ²⣬СÓÚÉè¼ÆÁËÒÔÏÂʵÑ飺£¨ÇëÄãÍê³ÉÏÂÁбí¸ñÖеĿհף©
  ʵÑé²½Öè ʵÑéÏÖÏó ʵÑé½áÂÛ
ʵÑé1     ²ÂÏë¢ÙÕýÈ·
ʵÑé2 ȡ̼ËáÇâÄÆÑùÆ·ÉÙÐí¼ÓÈëÊÔ¹ÜÖУ¬¼ÓÈÈ£¬²¢°Ñ²úÉúµÄÆøÌåͨÍù³ÎÇåµÄʯ»ÒË® ÊԹܿÚÓÐСˮµÎ²úÉú£¬ÓÐʹ³ÎÇåµÄË®»áË®±ä»ë×ǵÄÆøÌå²úÉú ²ÂÏë¢ÚÕýÈ·
ʵÑé½áÂÛ£ºNaHCO3ºÍ´×ËáÈÜÒº·´Ó¦ÓжþÑõ»¯Ì¼Éú³É£¬NaHCO3ÊÜÈÈ·Ö½âÒ²ÓжþÑõ»¯Ì¼²úÉú£®
¢ó£®²éÔÄ×ÊÁÏ£ºÔÚ°Ù¶ÈÍøÒ³ÖÐÊäÈë̼ËáÇâÄƵĻ¯Ñ§ÐÔÖÊ£¬¿ÉÒÔ»ñµÃ£¬Ì¼ËáÇâÄÆÊÜÈÈÒ׷ֽ⣬²úÎïÖÐÓÐ̼ËáÄÆÉú³É£¬ÔÙ¸ù¾ÝʵÑé2д³ö̼ËáÇâÄÆÊÜÈÈ·Ö½âµÄ»¯Ñ§·½³Ìʽ
 
£»
¢ô£®ÊµÑé2ÖÐÓа×É«·ÛÄ©Ê£Ó࣬ÇëÓÃÎïÀí·½·¨À´ÑéÖ¤Æä²»ÊÇÇâÑõ»¯ÄƹÌÌ壬Óû¯Ñ§·½·¨À´ÑéÖ¤Æä¿ÉÄÜ̼ËáÄƹÌÌ壻
£¨1£©ÎïÀí·½·¨£º
 
£»
£¨2£©»¯Ñ§·½·¨£º
 
£®
¢õ£®½áÂÛÓ¦ÓãºÔÚÕôÂøͷʱ£¬ÎÒÃÇͨ³£ÔÚ·¢½ÍºóµÄÃæÍÅÖмÓÈëСËÕ´ò£¨NaHCO3£©£¬¼ÓÈëNaHCO3µÄÄ¿µÄÊÇ
 
£®
´¿Ë®Ç峺͸Ã÷£¬²»º¬ÔÓÖʶøӲˮº¬Óн϶à¿ÉÈÜÐԸƺÍþµÄ»¯ºÏÎÏÖÓÐÁ½Æ¿ÎÞÉ«µÄÒºÌ壬·Ö±ðΪ´¿Ë®ºÍӲˮ£¬ÇëÄã²ÎÓëСö©Í¬Ñ§¶ÔË®µÄ̽¾¿£¬²¢»Ø´ðÓйØÎÊÌ⣺
£¨1£©ÀûÓÃÎü¸½¡¢³Áµí¡¢¹ýÂ˺ÍÕôÁóµÈ·½·¨¿É¾»»¯Ë®£¬ÆäÖÐÄܽµµÍË®µÄÓ²¶ÈµÄ·½·¨ÊÇ
ÕôÁó
ÕôÁó
£®
£¨2£©Çø±ð´¿Ë®ºÍӲˮµÄ·½·¨ÓжàÖÖ£®Ð¡ö©²ÉÓõķ½·¨ÊÇ·Ö±ðÈ¡ÑùÓÚÕô·¢ÃóÖУ¬¼ÓÈÈÕô¸É£¬ÓйÌÌåÎö³öµÄΪӲˮ£®ÇëÄãÉè¼ÆÁíÒ»ÖÖ·½·¨Çø·ÖËüÃÇ
È¡Ë®Ñù·Ö±ð·ÅÈëÁ½Ö§ÊÔ¹ÜÖУ¬¸÷µÎÈëÉÙÁ¿·ÊÔíË®Õñµ´£»ÅÝÄ­¶àµÄÊÇ´¿Ë®£¬ÅÝÄ­ÉÙµÄÊÇӲˮ
È¡Ë®Ñù·Ö±ð·ÅÈëÁ½Ö§ÊÔ¹ÜÖУ¬¸÷µÎÈëÉÙÁ¿·ÊÔíË®Õñµ´£»ÅÝÄ­¶àµÄÊÇ´¿Ë®£¬ÅÝÄ­ÉÙµÄÊÇӲˮ
£®
£¨3£©Ð¡ö©×öʵÑéʱ£¬·¢ÏÖӲˮÔÚ¼ÓÈȵĹý³ÌÖУ¬²úÉúÁËÉÙÁ¿ÆøÌå²¢µÃµ½Ò»ÖÖÄÑÈÜÐÔ¹ÌÌ壮
¡¾Ìá³ö²ÂÏë¡¿²úÉúµÄÆøÌå¿ÉÄÜÊǶþÑõ»¯Ì¼
¡¾Éè¼ÆʵÑé¡¿ÒªÖ¤Ã÷²úÉúµÄÆøÌåÊǶþÑõ»¯Ì¼£¬Îҵķ½·¨ÊÇ
½«ÆøÌåͨÈë³ÎÇåʯ»ÒË®ÖУ¬³ÎÇåʯ»ÒË®±ä»ë×Ç
½«ÆøÌåͨÈë³ÎÇåʯ»ÒË®ÖУ¬³ÎÇåʯ»ÒË®±ä»ë×Ç
£®
¡¾·´Ë¼¡¿]ÈËÃÇÔÚÉú²úÉú»îÖв»ÒËʹÓÃӲˮ£¬Çë¾ÙÒ»Àý˵Ã÷ʹÓÃӲˮÄÜÔì³ÉµÄΣº¦£º
ÓÃӲˮϴÒ·þ²úÉúµÄÅÝÄ­ºÜÉÙ£¬Ò·þ²»Ò×Ï´¸É¾»
ÓÃӲˮϴÒ·þ²úÉúµÄÅÝÄ­ºÜÉÙ£¬Ò·þ²»Ò×Ï´¸É¾»
£®ÔÚÈÕ³£Éú»îÖжÔÈçºÎ´¦ÀíӲˮÄãµÄ·½·¨ÊÇ
¼ÓÈÈÖó·Ð
¼ÓÈÈÖó·Ð
£®
»¯Ñ§ÓëÎÒÃǵÄÉú»îϢϢÏà¹Ø£®
£¨1£©Çë´ÓÑõÆø¡¢¶þÑõ»¯Ì¼¡¢Ð¡ËÕ´ò¡¢ÂÈ»¯ÄÆ¡¢Ë®ÎåÖÖÎïÖÊÖÐÑ¡ÔñÊʵ±µÄÎïÖÊ£¬Óû¯Ñ§Ê½Ìî¿Õ£º×î³£¼ûµÄÈܼÁÊÇ
H2O
H2O
£»×ö°ü×ÓÕôÂøͷʱʹÓ÷¢½Í·ÛµÄÖ÷Òª³É·ÖÊÇ
NaHCO3
NaHCO3
£»ÄܲúÉúÎÂÊÒЧӦµÄÆøÌåÊÇ
CO2
CO2
£®
£¨2£©ÇâÄÜÊÇÐÂÄÜÔ´¿ª·¢ÀûÓõÄÖØÒª·¢Õ¹·½Ïò£®¿Æѧ¼ÒÉèÏ룬ˮÔÚ´ß»¯¼ÁºÍ¹âÕÕÌõ¼þÏ·ֽâ¿ÉÖƵÃÇâÆø£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
2H2O
 ´ß»¯¼Á 
.
¹âÕÕ
2H2¡ü+O2¡ü
2H2O
 ´ß»¯¼Á 
.
¹âÕÕ
2H2¡ü+O2¡ü
£»Ò»Ñõ»¯Ì¼ºÍÇâÆøËä¾ßÓÐÏàͬµÄ»¯Ñ§ÐÔÖÊ£¬µ«Ò»Ñõ»¯Ì¼È´²»ÊÇÐÂÄÜÔ´µÄ·¢Õ¹·½Ïò£¬´Ó°²È«ºÍ»·±£µÄ½Ç¶ÈÀ´¿´£¬ÆäÖ÷ÒªÔ­ÒòÊÇ
Ò»Ñõ»¯Ì¼Óж¾£»Ò»Ñõ»¯Ì¼µÄȼÉÕ²úÎïÊǶþÑõ»¯Ì¼£¬ÄÜÔì³ÉÎÂÊÒЧӦ
Ò»Ñõ»¯Ì¼Óж¾£»Ò»Ñõ»¯Ì¼µÄȼÉÕ²úÎïÊǶþÑõ»¯Ì¼£¬ÄÜÔì³ÉÎÂÊÒЧӦ
£®
£¨3£©¼×´¼£¨CH3OH£©Óж¾£¬ÎóÒû¿ÉʹÑÛ¾¦Ê§Ã÷£¬ÉõÖÁËÀÍö£®×îÐÂÑо¿Ö¤Ã÷Óð±Æø£¨NH3£©´¦Àíº¬Óм״¼µÄ¹¤Òµ·ÏË®£¬¿Éת±äΪÎÞ¶¾µÄÎïÖÊ£¬»¯Ñ§·½³ÌʽΪ£º5CH3OH+12O2+6NH3
 Ï¸¾ú 
.
 
3X+5CO2+19H2O£®NH3ÖеªÔªËصĻ¯ºÏ¼ÛÊÇ
-3¼Û
-3¼Û
£»¼×´¼ÖÐÇâÔªËصÄÖÊÁ¿·ÖÊýΪ
12.5%
12.5%
£»XµÄ»¯Ñ§Ê½ÊÇ
N2
N2
£®
ÈËÃǵÄÉú»îÖÊÁ¿ÕýÔÚÖ𲽸ÄÉÆ£¬ÏÖ´ú³ø·¿ÖÐÓÐÐí¶àµÄ»¯Ñ§ÖªÊ¶£®
£¨1£©ÓеļÒͥʹÓõÄȼÁÏÊǹÞ×°Òº»¯Ê¯ÓÍÆø£¨ÈçͼËùʾ£©£¬ÆäÖ÷Òª³É·ÖÓбûÍ飨»¯Ñ§Ê½ÎªC3H8£©£¬ÊÇʯÓÍ»¯¹¤µÄÒ»ÖÖ²úÆ·£¬Ê¯ÓͲ»ÊôÓÚ
D
D
£®
A»ìºÏÎï    B»¯Ê¯ÄÜÔ´   C²»¿ÉÔÙÉúÄÜÔ´   D ¿ÉÔÙÉúÄÜÔ´
£¨2£©³£ÎÂÏ£¬Ò»¸öÈÝ»ýΪ35.5LµÄÒº»¯¹ÞÄÜװϼ¸°ÙÉýµÄ±ûÍ飬˵Ã÷±ûÍé·Ö×Ó
·Ö×ÓÖ®¼äÓмä¸ô
·Ö×ÓÖ®¼äÓмä¸ô
£®
£¨3£©±ûÍéÔÚ¿ÕÆøÖгä·ÖȼÉÕºóÉú³ÉÁ½ÖÖ³£¼ûÑõ»¯ÎÆ仯ѧ·½³ÌʽΪ£º
C3H8+5O2
 µãȼ 
.
 
3CO2+4H20
C3H8+5O2
 µãȼ 
.
 
3CO2+4H20
£®
£¨4£©³ø·¿×Å»ð£¬Ó¦¸ÃÁ¢¼´ÒÆ×ßÒº»¯¹Þ£¬ÕâÑù×öµÄÀíÓÉÊÇ
B
B
£®
A£®¸ô¾øÑõÆø  B£®Çå³ý¿ÉȼÎï  C£®½µµÍζȵ½¿ÉȼÎï×Å»ðµãÒÔÏÂ
£¨5£©³ø·¿ÊÇͬѧÃǵļÒͥʵÑéÊÒ£¬¿ÉÒÔÀûÓÃÐí¶àÉú»îÓÃÆ·½øÐÐʵÑé̽¾¿£®ÏÂÁÐʵÑéÖ»ÀûÓóø·¿ÖеÄÎïÆ·²»ÄÜÍê³ÉµÄÊÇ
B
B
£®
A£®¼ø±ðʳÑκʹ¿¼î            B£®¼ìÑé×ÔÀ´Ë®ÖÐÊÇ·ñº¬ÓÐÂÈÀë×Ó
C£®Ì½¾¿ÌúÖƲ˵¶µÄÉúÐâÌõ¼þ    D£®ÖÆÈ¡Î޿Ǽ¦µ°
£¨6£©²Í×ÀÉϵÄÓÍÎÛ¿ÉÓþƾ«³ýÈ¥£¬ÆäÔ­ÀíÊÇ
Èܽâ
Èܽâ
_£¬Ò²ÄÜÓÃÏ´½à¾«³ýÈ¥£¬ÆäÔ­ÀíÊÇ
È黯
È黯
£®
£¨7£©ÔÚ±ùÏäÖзÅÈëÓûîÐÔÌ¿ÖƳɵġ°³ý³ô¼Á¡±£¬Ëü¶Ô±ùÏäÀïµÄÒìζ¾ßÓÐ
Îü¸½
Îü¸½
×÷Óã®
£¨8£©ÇйýÏ̲˵IJ˵¶£¨Î´ÇåÏ´²Á¸É£©¸üÒ×ÉúÐ⣬ԭÒòÊÇ
ÌúÓëÑõÆøºÍË®³ä·Ö½Ó´¥Ê±ÈÝÒ×ÉúÐ⣬ÑÎÈÜÒºÄܹ»´Ù½ø²Ëµ¶ÉúÐâ
ÌúÓëÑõÆøºÍË®³ä·Ö½Ó´¥Ê±ÈÝÒ×ÉúÐ⣬ÑÎÈÜÒºÄܹ»´Ù½ø²Ëµ¶ÉúÐâ
£®
£¨9£©ÆÊÓãʱ²»Ð¡ÐÄŪÆÆÁËÓ㵨£¬µ¨Ö­Ê¹ÓãÈâ´øÓпà棬µ¨Ö­ÖвúÉú¿àζµÄÖ÷Òª³É·ÖÊǵ¨Ö­ËᣨÊôËáÀࣩ£®¸ù¾ÝÄãËùÕÆÎÕµÄ֪ʶ£¬Çå³ý¿à棬×îºÃʹÓÃ
D
D
£®
£¨A£© ÉÕ¼îÈÜÒº            £¨B£©Ê³´×              £¨C£©Ê³ÑÎË®         £¨D£© ´¿¼îÈÜÒº
£¨10£©×öÂøÍ··¢½ÍÃæÍÅʱ£¬»á²úÉúÈéËáµÈÓлúËᣬÕôÂøÍ·Ç°Ðè¼Ó½øÊÊÁ¿µÄ´¿¼î»òСËÕ´òµÈ¼îÐÔÎïÖÊ£¬ËüÃÇÏ໥×÷ÓòúÉúÁË
¶þÑõ»¯Ì¼
¶þÑõ»¯Ì¼
ÆøÌ壬ʹÕô³öµÄÂøÍ·ÊèËɶà¿×£»Èô¼ÓÈëµÄ¼îÐÔÎïÖʹý¶à£¬¿ÉÏòÃæÍÅ»òÕô¹øÖеμÓÉÙÐíº¬
´×Ëá
´×Ëá
µÄËáÐÔµ÷ζÁÏ£¬·ñÔòÕô³öµÄÂøÍ·»á±äɬ£¬ÑÕÉ«·¢»Æ£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø