题目内容
| 3 |
| 2 |
| 5 |
| 4 |
| 9 |
| 8 |
| 17 |
| 16 |
| 257 |
| 256 |
分析:这道题有一个明显的特点:分子都比分母1大1.因此把1拿出来以后,剩下的分数能过拆分为两个分数相减的形式,然后通过加、减相抵消的方法,求得结果.
解答:解:
+
+
+
+…+
,
=1+
+1+
+1+
+1+
+…+1+
,
=(1+1+1+1+…+1)+(
+
+
+
+…+
),
=8+(1-
+
-
+
-
+
-
+…+
-
),
=8+(1-
),
=8+
,
=8
.
| 3 |
| 2 |
| 5 |
| 4 |
| 9 |
| 8 |
| 17 |
| 16 |
| 257 |
| 256 |
=1+
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 16 |
| 1 |
| 256 |
=(1+1+1+1+…+1)+(
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 16 |
| 1 |
| 256 |
=8+(1-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 8 |
| 1 |
| 16 |
| 1 |
| 128 |
| 1 |
| 256 |
=8+(1-
| 1 |
| 256 |
=8+
| 255 |
| 256 |
=8
| 255 |
| 256 |
点评:在解答分数拆项的题目,应注意审题,拆开后的分数要相互抵消.
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