题目内容

用递等式计算
5
5
12
-(1
7
8
÷4
1
2
+
3
4
×1
1
5
10
1
2
÷
[(3.5+2.8)×
1
7
]
3÷
7
8
-
3
4
÷3-
3
4
×3
1
4
×3.2
+2.8÷2
3
5
4-(10.9-5
2
5
×1
1
3
7.8×[32×(1-
5
8
)
+3.6].
(1)5
5
12
-(1
7
8
÷4
1
2
+
3
4
×1
1
5
),
=5
5
12
-(
5
12
+
9
10
),
═5
5
12
-
5
12
-
9
10

=5-
9
10

=4
1
10


(2)10
1
2
÷
[(3.5+2.8)×
1
7
],
=10
1
2
÷
[6.3×
1
7
],
=10
1
2
÷
0.9,
=
210
18


(3)3÷
7
8
-
3
4
÷3-
3
4
×3,
=
24
7
-
1
4
-
9
4

=
24
7
-(
1
4
+
9
4
),
=
24
7
-
5
2

=
13
14


(4)
1
4
×3.2+2.8÷2
3
5

=0.8+
14
13

=
122
65


(5)4-(10.9-5
2
5
×1
1
3
),
=4-(10.9-7.2),
=4-3.7,
=0.3;

(6)7.8×[32×(1-
5
8
)
+3.6],
=7.8×[32×
3
8
+3.6],
=7.8×[12+3.6],
=7.8×15.6,
=121.68.
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