题目内容
用递等式计算
5
| 10
| 3÷
| ||||||||||||||||||||
| 4-(10.9-5
| 7.8×[32×(1-
|
(1)5
-(1
÷4
+
×1
),
=5
-(
+
),
═5
-
-
,
=5-
,
=4
;
(2)10
÷[(3.5+2.8)×
],
=10
÷[6.3×
],
=10
÷0.9,
=
;
(3)3÷
-
÷3-
×3,
=
-
-
,
=
-(
+
),
=
-
,
=
;
(4)
×3.2+2.8÷2
,
=0.8+
,
=
;
(5)4-(10.9-5
×1
),
=4-(10.9-7.2),
=4-3.7,
=0.3;
(6)7.8×[32×(1-
)+3.6],
=7.8×[32×
+3.6],
=7.8×[12+3.6],
=7.8×15.6,
=121.68.
| 5 |
| 12 |
| 7 |
| 8 |
| 1 |
| 2 |
| 3 |
| 4 |
| 1 |
| 5 |
=5
| 5 |
| 12 |
| 5 |
| 12 |
| 9 |
| 10 |
═5
| 5 |
| 12 |
| 5 |
| 12 |
| 9 |
| 10 |
=5-
| 9 |
| 10 |
=4
| 1 |
| 10 |
(2)10
| 1 |
| 2 |
| 1 |
| 7 |
=10
| 1 |
| 2 |
| 1 |
| 7 |
=10
| 1 |
| 2 |
=
| 210 |
| 18 |
(3)3÷
| 7 |
| 8 |
| 3 |
| 4 |
| 3 |
| 4 |
=
| 24 |
| 7 |
| 1 |
| 4 |
| 9 |
| 4 |
=
| 24 |
| 7 |
| 1 |
| 4 |
| 9 |
| 4 |
=
| 24 |
| 7 |
| 5 |
| 2 |
=
| 13 |
| 14 |
(4)
| 1 |
| 4 |
| 3 |
| 5 |
=0.8+
| 14 |
| 13 |
=
| 122 |
| 65 |
(5)4-(10.9-5
| 2 |
| 5 |
| 1 |
| 3 |
=4-(10.9-7.2),
=4-3.7,
=0.3;
(6)7.8×[32×(1-
| 5 |
| 8 |
=7.8×[32×
| 3 |
| 8 |
=7.8×[12+3.6],
=7.8×15.6,
=121.68.
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