题目内容
[1
+
×
]÷2
=1.
| 4 |
| 5 |
| 2 |
| 9 |
| 15 |
| 4 |
| 15 |
| 4 |
| 19 |
| 30 |
分析:此题可设括号内的数为x,得:[1
+
×x]÷2
=1,通过解方程求出结果.
| 4 |
| 5 |
| 2 |
| 9 |
| 19 |
| 30 |
解答:解:设括号内的数为x,得:
[1
+
×x]÷2
=1
[1
+
×x]÷2
×2
=1×2
1
+
×x=2
1
+
×x-1
=2
-1
x=
x×
=
×
x=
.
故答案为:
.
[1
| 4 |
| 5 |
| 2 |
| 9 |
| 19 |
| 30 |
[1
| 4 |
| 5 |
| 2 |
| 9 |
| 19 |
| 30 |
| 19 |
| 30 |
| 19 |
| 30 |
1
| 4 |
| 5 |
| 2 |
| 9 |
| 19 |
| 30 |
1
| 4 |
| 5 |
| 2 |
| 9 |
| 4 |
| 5 |
| 19 |
| 30 |
| 4 |
| 5 |
| 2 |
| 9 |
| 5 |
| 6 |
| 2 |
| 9 |
| 9 |
| 2 |
| 5 |
| 6 |
| 9 |
| 2 |
x=
| 15 |
| 4 |
故答案为:
| 15 |
| 4 |
点评:此题也可运用加减乘除的逆运算关系求解,列式为(1×2
-1
)÷
,计算即可.
| 19 |
| 30 |
| 4 |
| 5 |
| 2 |
| 9 |
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