题目内容
脱式计算:
(1)12×(
+
)
(2)
×
÷
×
(3)1
×
+
÷
.
(1)12×(
| 3 |
| 4 |
| 1 |
| 2 |
(2)
| 2 |
| 5 |
| 1 |
| 2 |
| 2 |
| 5 |
| 1 |
| 2 |
(3)1
| 3 |
| 2 |
| 2 |
| 5 |
| 1 |
| 4 |
| 3 |
| 4 |
(1)12×(
+
),
=12×
+12×
,
=9+6,
=15;
(2)
×
÷
×
,
=
÷
×
,
=
×
,
=
;
(3)1
×
+
÷
,
=1+
,
=1
.
| 3 |
| 4 |
| 1 |
| 2 |
=12×
| 3 |
| 4 |
| 1 |
| 2 |
=9+6,
=15;
(2)
| 2 |
| 5 |
| 1 |
| 2 |
| 2 |
| 5 |
| 1 |
| 2 |
=
| 1 |
| 5 |
| 2 |
| 5 |
| 1 |
| 2 |
=
| 1 |
| 2 |
| 1 |
| 2 |
=
| 1 |
| 4 |
(3)1
| 3 |
| 2 |
| 2 |
| 5 |
| 1 |
| 4 |
| 3 |
| 4 |
=1+
| 1 |
| 3 |
=1
| 1 |
| 3 |
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