题目内容
脱式计算
(1)(
|
(2)(
| ||||||||||||||||
(3)
|
(4)31
|
分析:(1)(2)(4)依据四则运算计算顺序解答,
(3)运用乘法分配律解答.
(3)运用乘法分配律解答.
解答:解:(1)(
+
)÷(
×
),
=
÷
,
=1
;
(2)(
-
+
)÷
,
=(
+
)÷
,
=
÷
,
=1
;
(3)
×
+
÷
,
=(
+
)×
,
=1×
,
=
;
(4)31
×
+1
×
,
=26+1,
=27.
| 5 |
| 4 |
| 5 |
| 4 |
| 5 |
| 4 |
| 5 |
| 4 |
=
| 5 |
| 2 |
| 25 |
| 16 |
=1
| 3 |
| 5 |
(2)(
| 2 |
| 3 |
| 2 |
| 11 |
| 1 |
| 2 |
| 1 |
| 2 |
=(
| 16 |
| 33 |
| 1 |
| 2 |
| 1 |
| 2 |
=
| 65 |
| 66 |
| 1 |
| 2 |
=1
| 32 |
| 33 |
(3)
| 3 |
| 5 |
| 7 |
| 15 |
| 8 |
| 15 |
| 5 |
| 3 |
=(
| 7 |
| 15 |
| 8 |
| 15 |
| 3 |
| 5 |
=1×
| 3 |
| 5 |
=
| 3 |
| 5 |
(4)31
| 1 |
| 5 |
| 5 |
| 6 |
| 1 |
| 8 |
| 8 |
| 9 |
=26+1,
=27.
点评:本题主要考查学生依据四则运算计算顺序,以及运用乘法分配律解决问题的能力,注意计算结果的准确性.
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