题目内容
用递等式计算．
| （1）2184-[（44×19+44）÷5] | （2）450+（8.16+6.84）÷0.63 | ||||||||||||||
（3）(
| （4）[1-（
| ||||||||||||||
（5）（4-7.5×
| （6）
|
（1）2184-[（44×19+44）÷5]，
=2184-[44×（19+1）÷5]，
=2184-[44×20÷5]，
=2184-[880÷5]，
=2184-176，
=2008；
（2）450+（8.16+6.84）÷0.63，
=450+15÷0.63，
=450+23
| 17 |
| 21 |
=473
| 17 |
| 21 |
（3）(
| 4 |
| 5 |
| 1 |
| 4 |
| 7 |
| 5 |
| 5 |
| 6 |
=
| 21 |
| 20 |
| 7 |
| 5 |
| 5 |
| 6 |
=
| 3 |
| 4 |
| 5 |
| 6 |
=
| 19 |
| 12 |
（4）[1-（
| 1 |
| 12 |
| 1 |
| 8 |
| 1 |
| 12 |
=[1-
| 5 |
| 24 |
| 1 |
| 12 |
=[1-
| 5 |
| 12 |
| 1 |
| 12 |
=
| 7 |
| 12 |
| 1 |
| 12 |
=7；
（5）（4-7.5×
| 4 |
| 15 |
| 2 |
| 9 |
=（4-2）÷
| 2 |
| 9 |
=2÷
| 2 |
| 9 |
=9；
（6）
| 7 |
| 12 |
| 1 |
| 4 |
| 8 |
| 9 |
| 1 |
| 4 |
=
| 7 |
| 12 |
| 8 |
| 9 |
| 1 |
| 4 |
=
| 7 |
| 12 |
| 1 |
| 4 |
=
| 7 |
| 12 |
| 1 |
| 4 |
=
| 1 |
| 3 |
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