题目内容
100-98.2-1.8.
8
+4.7+1
+5.3
14.71-5
-4
.
8
| 3 |
| 4 |
| 1 |
| 4 |
14.71-5
| 7 |
| 8 |
| 1 |
| 8 |
分析:分别利用加法交换律、加法的结合律、连减的性质简算.
解答:解:①100-98.2-1.8
=100-(98.2+1.8)
=100-100
=0;
②8
+4.7+1
+5.3
=(8
+1
)+(4.7+5.3)
=10+10
=20;
③14.71-5
-4
=14.71-(5
+4
)
=14.71-10
=4.71.
=100-(98.2+1.8)
=100-100
=0;
②8
| 3 |
| 4 |
| 1 |
| 4 |
=(8
| 3 |
| 4 |
| 1 |
| 4 |
=10+10
=20;
③14.71-5
| 7 |
| 8 |
| 1 |
| 8 |
=14.71-(5
| 7 |
| 8 |
| 1 |
| 8 |
=14.71-10
=4.71.
点评:本题要求学生能合理利用运算定律、连减的性质进行简算.
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