题目内容
(2012?罗源县)解方程或比例.
①3x+
=10.5
②0.25:
=
:x.
①3x+
| 9 |
| 2 |
②0.25:
| 9 |
| 4 |
| 1 |
| 3 |
分析:(1)根据等式的性质,在方程两边同时减去
,再除以3求解,
(2)先根据等式的性质,把原式转化为0.25x=
×
,再根据等式的性质,在方程两边同时除以0.25求解.
| 9 |
| 2 |
(2)先根据等式的性质,把原式转化为0.25x=
| 9 |
| 4 |
| 1 |
| 3 |
解答:解:(1)3x+
=10.5,
3x+
-
=10.5-
,
3x÷3=6÷3,
x=2;
(2)0.25:
=
:x,
0.25x=
×
,
0.25x÷0.25=
÷0.25,
x=3.
| 9 |
| 2 |
3x+
| 9 |
| 2 |
| 9 |
| 2 |
| 9 |
| 2 |
3x÷3=6÷3,
x=2;
(2)0.25:
| 9 |
| 4 |
| 1 |
| 3 |
0.25x=
| 9 |
| 4 |
| 1 |
| 3 |
0.25x÷0.25=
| 3 |
| 4 |
x=3.
点评:本题考查了学生根据等式的性质和比例的基本性质解方程的能力,注意等号对齐.
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