题目内容
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分析:原式变为
x+
=x+1,根据等式的性质,两边同减去
,得
x=x-
,两边同减去
x,得
x-
=0,两边同加上
,然后再同乘4即可.
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解答:解:
(x+2)=x+1
x+
=x+1
x+
-
=x+1-
x=x-
x-
x=x-
-
x
x-
=0
x-
+
=0+
x=
x×4=
×4
x=2.
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x=2.
点评:此题考查了运用等式的性质解方程,即等式两边同加上或同减去、同乘上或同除以一个数(0除外),两边仍相等,同时注意“=”上下要对齐.
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