题目内容
用合理的方法计算.
÷[
×(
+
)]
5.6×3
-4
×3.75+0.88×37
(947
+94
+9.476+0.9476)÷0.1111
.
| 1 |
| 16 |
| 1 |
| 25 |
| 2 |
| 5 |
| 1 |
| 10 |
5.6×3
| 3 |
| 4 |
| 2 |
| 5 |
| 1 |
| 2 |
(947
| 3 |
| 5 |
| 19 |
| 25 |
| 2011×(3.4×69+3.5) |
| 3.5×69-3.4 |
(1)
÷[
×(
+
)],
=
÷[
×(
+
)],
=
÷[
×
],
=
÷
,
=
×50,
=
;
(2)5.6×3
-4
×3.75+0.88×37
,
=5.6×3.75-4.4×3.75+0.88×37.5,
=5.6×3.75-4.4×3.75+8.8×3.75,
=(5.6-4.4+8.8)×3.75,
=10×3.75,
=37.5;
(3)(947
+94
+9.476+0.9476)÷0.1111,
=(947.6+94.76+9.476+0.9476)÷0.1111,
=(9476×0.1+9476×0.01+9476×0.001+9476×0.0001)÷0.1111,
=[(0.1+0.01+0.001+0.0001)×9476]÷0.1111,
=0.1111×9476÷0.1111,
=9476;
(4)
,
=
,
=
,
=
,
=2011.
| 1 |
| 16 |
| 1 |
| 25 |
| 2 |
| 5 |
| 1 |
| 10 |
=
| 1 |
| 16 |
| 1 |
| 25 |
| 4 |
| 10 |
| 1 |
| 10 |
=
| 1 |
| 16 |
| 1 |
| 25 |
| 1 |
| 2 |
=
| 1 |
| 16 |
| 1 |
| 50 |
=
| 1 |
| 16 |
=
| 25 |
| 8 |
(2)5.6×3
| 3 |
| 4 |
| 2 |
| 5 |
| 1 |
| 2 |
=5.6×3.75-4.4×3.75+0.88×37.5,
=5.6×3.75-4.4×3.75+8.8×3.75,
=(5.6-4.4+8.8)×3.75,
=10×3.75,
=37.5;
(3)(947
| 3 |
| 5 |
| 19 |
| 25 |
=(947.6+94.76+9.476+0.9476)÷0.1111,
=(9476×0.1+9476×0.01+9476×0.001+9476×0.0001)÷0.1111,
=[(0.1+0.01+0.001+0.0001)×9476]÷0.1111,
=0.1111×9476÷0.1111,
=9476;
(4)
| 2011×(3.4×69+3.5) |
| 3.5×69-3.4 |
=
| 2011×[3.4×(70-1)+3.5] |
| [(3.4+0.1)×69-3.4] |
=
| 2011×(3.4×70+0.1) |
| 3.4×69+3.5 |
=
| 2011×(3.4×70+0.1) |
| 3.4×70+0.1 |
=2011.
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