题目内容
求未知数x.
(1)3X:
=21:
(2)
X+1=2X-0.2.
(1)3X:
| 5 |
| 14 |
| 5 |
| 8 |
(2)
| 1 |
| 8 |
分析:(1)根据比例的基本性质,把原式转化为3×
x=
×21,再根据等式的性质,在方程两边同时乘
解答.
(2)根据等式的性质,在方程两边同时减去
x,再加上0.2,最后乘上
解答.
| 5 |
| 8 |
| 5 |
| 14 |
| 8 |
| 15 |
(2)根据等式的性质,在方程两边同时减去
| 1 |
| 8 |
| 8 |
| 15 |
解答:解:(1)3x:
=21:
,
3×
x=
×21,
x=
,
x×
=
×
,
x=4;
(2)
x+1=2x-0.2,
x+1-
x=2x-0.2-
x,
x-0.2=1,
x-0.2+0.2=1+0.2,
x×
=1.2×
,
x=
.
| 5 |
| 14 |
| 5 |
| 8 |
3×
| 5 |
| 8 |
| 5 |
| 14 |
| 15 |
| 8 |
| 15 |
| 2 |
| 15 |
| 8 |
| 8 |
| 15 |
| 15 |
| 2 |
| 8 |
| 15 |
x=4;
(2)
| 1 |
| 8 |
| 1 |
| 8 |
| 1 |
| 8 |
| 1 |
| 8 |
| 15 |
| 8 |
| 15 |
| 8 |
| 15 |
| 8 |
| 8 |
| 15 |
| 8 |
| 15 |
x=
| 16 |
| 25 |
点评:本题考查了学生根据比例的基本性质和等式的性质解方程的能力.
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