题目内容
能简算的要简算
(
+
)÷
÷
+
×8
42000÷125÷8
×[
-(
+
)].
(
| 3 |
| 4 |
| 5 |
| 16 |
| 1 |
| 36 |
| 5 |
| 7 |
| 1 |
| 8 |
| 2 |
| 7 |
42000÷125÷8
| 15 |
| 8 |
| 4 |
| 5 |
| 1 |
| 5 |
| 1 |
| 3 |
分析:(1)(4)根据四则混合运算的运算顺序计算即可;
(2)可根据乘法分配律计算;
(3)可根据一个数除以两个数,等于用这个数除以这两个数的积的除法性质计算;
(2)可根据乘法分配律计算;
(3)可根据一个数除以两个数,等于用这个数除以这两个数的积的除法性质计算;
解答:解:(1)(
+
)÷
=
×36,
=
;
(2)
÷
+
×8
=
×8+
×8,
=(
+
)×8,
=1×8,
=8;
(3)42000÷125÷8
=42000÷(125×8),
=42000÷1000,
=42;
(4)
×[
-(
+
)]
=
×[
-
],
=
×
,
=
.
| 3 |
| 4 |
| 5 |
| 16 |
| 1 |
| 36 |
=
| 17 |
| 16 |
=
| 153 |
| 4 |
(2)
| 5 |
| 7 |
| 1 |
| 8 |
| 2 |
| 7 |
=
| 5 |
| 7 |
| 2 |
| 7 |
=(
| 5 |
| 7 |
| 2 |
| 7 |
=1×8,
=8;
(3)42000÷125÷8
=42000÷(125×8),
=42000÷1000,
=42;
(4)
| 15 |
| 8 |
| 4 |
| 5 |
| 1 |
| 5 |
| 1 |
| 3 |
=
| 15 |
| 8 |
| 4 |
| 5 |
| 8 |
| 15 |
=
| 15 |
| 8 |
| 4 |
| 15 |
=
| 1 |
| 2 |
点评:当算式中同时含有中括号与小括号时,要注意先算中括号里面的,再算小括号里面的.
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