题目内容
(1+
+
+
)×(
+
+
+
)-(1+
+
+
+
)×(
+
+
)=
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(1+
+
+
)×(
+
+
+
)-(1+
+
+
+
)×(
+
+
)
设设a=1+
+
+
,b=
+
+
,所以原式化为:
a×(b+
)-(a+
)×b
=a×b+
×a-a×b-
×b,
=
×(a-b),
=
×[(1+
+
+
)-(
+
+
)],
=
.
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设设a=1+
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a×(b+
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=a×b+
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=
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=
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=
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