题目内容
(2010?临澧县)
解方程.
|
|
(1-
|
分析:(1)根据等式的性质,两边同乘
,再同乘
即可;
(2)先根据乘法分配律改写成(
+
)x=
,即
x=
,再根据等式的性质,两边同乘
即可;
(3)先计算1-
=
,再根据等式的性质,两边同乘
即可.
| 1 |
| 6 |
| 4 |
| 3 |
(2)先根据乘法分配律改写成(
| 1 |
| 8 |
| 3 |
| 4 |
| 35 |
| 64 |
| 7 |
| 8 |
| 35 |
| 64 |
| 8 |
| 7 |
(3)先计算1-
| 5 |
| 8 |
| 3 |
| 8 |
| 8 |
| 3 |
解答:解:(1)
x÷
=18,
x÷
×
=18×
,
x=3,
x×
=3×
,
x=4;
(2)
x+
x=
,
(
+
)x=
,
x=
,
x×
=
×
,
x=
;
(3)(1-
)x=
,
x=
,
x×
=
×
,
x=
.
| 3 |
| 4 |
| 1 |
| 6 |
| 3 |
| 4 |
| 1 |
| 6 |
| 1 |
| 6 |
| 1 |
| 6 |
| 3 |
| 4 |
| 3 |
| 4 |
| 4 |
| 3 |
| 4 |
| 3 |
x=4;
(2)
| 1 |
| 8 |
| 3 |
| 4 |
| 35 |
| 64 |
(
| 1 |
| 8 |
| 3 |
| 4 |
| 35 |
| 64 |
| 7 |
| 8 |
| 35 |
| 64 |
| 7 |
| 8 |
| 8 |
| 7 |
| 35 |
| 64 |
| 8 |
| 7 |
x=
| 5 |
| 8 |
(3)(1-
| 5 |
| 8 |
| 15 |
| 14 |
| 3 |
| 8 |
| 15 |
| 14 |
| 3 |
| 8 |
| 8 |
| 3 |
| 15 |
| 14 |
| 8 |
| 3 |
x=
| 20 |
| 7 |
点评:此题考查了根据等式的性质解方程,即等式两边同加、同减、同乘或同除以一个数(0除外),等式的左右两边仍相等;注意等号上下要对齐.
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