题目内容
已知a=4322×1233,b=4321×1234;下列结论正确的是( )
| A、a<b | B、a=b | C、a>b |
分析:分别把4322变成(4321+1),1234变成(1233+1),再根据乘法分配律,进行运算,据此解答.
解答:解:a=4322×1233
=(4321+1)×1233
=4321×1233+1233
b=4321×1234
=4321×(1233+1)
=4321×1233+4321
4321×1233+1233<4321×1233+4321,
故选:A.
=(4321+1)×1233
=4321×1233+1233
b=4321×1234
=4321×(1233+1)
=4321×1233+4321
4321×1233+1233<4321×1233+4321,
故选:A.
点评:本题考查了学生灵活运用乘法分配律的能力.
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