题目内容

计算:
(1)1
3
4
×18.35-9
7
20
×1.75+3.5×
1
2

(2)1
1
24
×[(1.5+2
2
3
)÷3.75-
2
3
8
9


(3)[2-(8.25-5
1
3
2
3
]÷0.9

(4)2
2
3
×(1
7
8
-
5
6
)÷[3
1
4
÷(
1
8
+1
5
6
)]
(1)1
3
4
×18.35-9
7
20
×1.75+3.5×
1
2

=1.75×18.35-9.35×1.75+1.75,
=(18.35-9.35+1)×1.75,
=10×1.75,
=17.5;

(2)1
1
24
×[(1.5+2
2
3
)÷3.75-
2
3
8
9

=
25
24
×[(
3
2
+
8
3
)×
4
15
-
2
3
9
8

=
25
24
×[
25
6
×
4
15
-
2
3
9
8

=
25
24
×[(
10
9
-
2
3
9
8

=
25
24
×
4
9
×
9
8

=
25
48


(3)[2-(8.25-5
1
3
2
3
]÷0.9

=[2-(
33
4
-
16
3
)×
2
3
]÷0.9,
=[2-
35
12
×
2
3
]÷0.9,
=[2-
35
18
10
9

=
1
18
×
10
9

=
5
81


(4)2
2
3
×(1
7
8
-
5
6
)÷[3
1
4
÷(
1
8
+1
5
6
)]

=
8
3
×
25
24
÷[
13
4
×
24
47
],
=
25
9
×
47
78

=
1175
702
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