题目内容
解方程.
(1)
χ-
÷
=
(2)
χ-0.4χ=
.
(1)
| 1 |
| 3 |
| 5 |
| 16 |
| 15 |
| 8 |
| 2 |
| 3 |
(2)
| 2 |
| 3 |
| 1 |
| 6 |
分析:(1)先化简,再根据等式的性质,在方程两边同时加上
,再乘3求解,
(2)先化简,再根据等式的性质,在方程两边同时乘
求解.
| 1 |
| 6 |
(2)先化简,再根据等式的性质,在方程两边同时乘
| 15 |
| 4 |
解答:解:(1)
X-
÷
=
,
X-
=
,
X-
+
=
+
,
X×3=
×3,
X=2
;
(2)
X-0.4X=
,
X=
,
X×
=
×
,
X=
.
| 1 |
| 3 |
| 5 |
| 16 |
| 15 |
| 8 |
| 2 |
| 3 |
| 1 |
| 3 |
| 1 |
| 6 |
| 2 |
| 3 |
| 1 |
| 3 |
| 1 |
| 6 |
| 1 |
| 6 |
| 2 |
| 3 |
| 1 |
| 6 |
| 1 |
| 3 |
| 5 |
| 6 |
X=2
| 1 |
| 2 |
(2)
| 2 |
| 3 |
| 1 |
| 6 |
| 4 |
| 15 |
| 1 |
| 6 |
| 4 |
| 15 |
| 15 |
| 4 |
| 1 |
| 6 |
| 15 |
| 4 |
X=
| 5 |
| 8 |
点评:本题考查了学生根据等式的性质解方程的能力,注意等号对齐.
练习册系列答案
相关题目