题目内容
计算:
(1)
+
(2)2
-
(3)4
×
(4)7÷3
.
(1)
| 3 |
| 5 |
| 1 |
| 4 |
(2)2
| 1 |
| 4 |
| 2 |
| 3 |
(3)4
| 5 |
| 6 |
| 6 |
| 7 |
(4)7÷3
| 1 |
| 4 |
分析:(1)、(2)先通分再相加减;
(3)把4
化成假分数后再相乘;
(4)先把3
化成假分数,再用7乘它的倒数即可.
(3)把4
| 5 |
| 6 |
(4)先把3
| 1 |
| 4 |
解答:解:(1)
+
,
=
+
,
=
;
(2)2
-
,
=
-
,
=
-
,
=
;
(3)4
×
,
=
×
,
=
;
(4)7÷3
,
=7÷
,
=7×
,
=
.
| 3 |
| 5 |
| 1 |
| 4 |
=
| 12 |
| 20 |
| 5 |
| 20 |
=
| 17 |
| 20 |
(2)2
| 1 |
| 4 |
| 2 |
| 3 |
=
| 9 |
| 4 |
| 2 |
| 3 |
=
| 27 |
| 12 |
| 8 |
| 12 |
=
| 19 |
| 12 |
(3)4
| 5 |
| 6 |
| 6 |
| 7 |
=
| 29 |
| 6 |
| 6 |
| 7 |
=
| 29 |
| 7 |
(4)7÷3
| 1 |
| 4 |
=7÷
| 13 |
| 4 |
=7×
| 4 |
| 13 |
=
| 28 |
| 13 |
点评:本题考查了基本的分数加减乘除的计算,按照各自的运算法则计算即可.
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