题目内容
(2011?郑州模拟)用合理的方法计算:
(1)
+
×
(2)
×2007
(3)(
+
)×8+
(4)
×(
+
÷
)
(5)
÷[1÷(
-
)].
(1)
2 |
3 |
1 |
3 |
3 |
4 |
(2)
2005 |
2006 |
(3)(
5 |
8 |
1 |
27 |
19 |
27 |
(4)
3 |
5 |
1 |
7 |
8 |
21 |
2 |
3 |
(5)
1 |
6 |
3 |
5 |
3 |
10 |
分析:(1)
+
×
,按运算顺序进行计算,先算乘法,再算加法;
(2)
×2007,把2007看作2006+1,然后用乘法分配律计算;
(3)(
+
)×8+
,先用乘法分配律计算(
+
)×8,然后用加法结合律;
(4)
×(
+
÷
),按运算顺序进行计算,先算括号里的,再算括号外的;
(5)
÷[1÷(
-
)],按运算顺序进行计算,先算小括号里的,再算中括号里的,最后算括号外的.
2 |
3 |
1 |
3 |
3 |
4 |
(2)
2005 |
2006 |
(3)(
5 |
8 |
1 |
27 |
19 |
27 |
5 |
8 |
1 |
27 |
(4)
3 |
5 |
1 |
7 |
8 |
21 |
2 |
3 |
(5)
1 |
6 |
3 |
5 |
3 |
10 |
解答:解:(1)
+
×
,
=
+
,
=
+
,
=
;
(2)
×2007,
=
×(2006+1),
=
×2006+
,
=2005+
,
=2005
;
(3)(
+
)×8+
,
=
×8+
×8+
,
=5+(
+
),
=5+1,
=6;
(4)
×(
+
÷
),
=
×(
+
×
),
=
×(
+
),
=
×
,
=
;
(5)
÷[1÷(
-
)],
=
÷[1÷(
-
)],
=
÷[1÷
],
=
÷
,
=
×
,
=
.
2 |
3 |
1 |
3 |
3 |
4 |
=
2 |
3 |
1 |
4 |
=
8 |
12 |
3 |
12 |
=
11 |
12 |
(2)
2005 |
2006 |
=
2005 |
2006 |
=
2005 |
2006 |
2005 |
2006 |
=2005+
2005 |
2006 |
=2005
2005 |
2006 |
(3)(
5 |
8 |
1 |
27 |
19 |
27 |
=
5 |
8 |
1 |
27 |
19 |
27 |
=5+(
8 |
27 |
19 |
27 |
=5+1,
=6;
(4)
3 |
5 |
1 |
7 |
8 |
21 |
2 |
3 |
=
3 |
5 |
1 |
7 |
8 |
21 |
3 |
2 |
=
3 |
5 |
1 |
7 |
4 |
7 |
=
3 |
5 |
5 |
7 |
=
3 |
7 |
(5)
1 |
6 |
3 |
5 |
3 |
10 |
=
1 |
6 |
6 |
10 |
3 |
10 |
=
1 |
6 |
3 |
10 |
=
1 |
6 |
10 |
3 |
=
1 |
6 |
3 |
10 |
=
1 |
20 |
点评:此题考查学生对分数四则混合运算顺序的掌握,以及灵活运用运算定律巧算的能力.
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