题目内容
脱式计算下面各题
20100-14874÷37
1
÷(5-3.9×
)=
(6-0.558)÷9.07×(0.7-0.075)=
6.3×[(10
-3
)÷6
]÷1
=
1
×2
÷[9÷(8+2
)]=
[14.8+(3
-1.5)×1
]÷2
=
20100-14874÷37
1
| 5 |
| 7 |
| 2 |
| 3 |
(6-0.558)÷9.07×(0.7-0.075)=
6.3×[(10
| 1 |
| 3 |
| 1 |
| 2 |
| 5 |
| 6 |
| 4 |
| 5 |
1
| 1 |
| 2 |
| 1 |
| 4 |
| 2 |
| 3 |
[14.8+(3
| 3 |
| 7 |
| 3 |
| 25 |
| 2 |
| 3 |
分析:(1)先算除法,再算加法.
(2)先算括号中的乘法,再算减法,最后算除法.
(3)先算括号中的减法,再算除法,最后算乘法.
(4)先算小括号内的减法,再算中括号内的除法,最后算乘法及除法.
(5)先算小括号内的加法,再算中括号内的除法,然后算乘法,最后算除法.
(6)先算小括号内的减法,再算中括号内的乘法,然后算加法,最后算除法.
(2)先算括号中的乘法,再算减法,最后算除法.
(3)先算括号中的减法,再算除法,最后算乘法.
(4)先算小括号内的减法,再算中括号内的除法,最后算乘法及除法.
(5)先算小括号内的加法,再算中括号内的除法,然后算乘法,最后算除法.
(6)先算小括号内的减法,再算中括号内的乘法,然后算加法,最后算除法.
解答:解:(1)20100-14874÷37
=20100-402
=19698;
(2)1
÷(5-3.9×
)
=1
÷(5-2.6)
=
×
=
;
(3)(6-0.558)÷9.07×(0.7-0.075)
=5.442÷9.07×0.625
=0.6×0.625
=0.375;
(4)6.3×[(10
-3
)÷6
]÷1
=6.3×(
×
)×
=6.3×
=3.5;
(5)1
×2
÷[9÷(8+2
)]
=
×
÷(9÷
)
=
×
×
×
=4;
(6)[14.8+(3
-1.5)×1
]÷2
=(14.8+
×
)×
=(14.8+1.92)×
=16.72×
=6.27.
=20100-402
=19698;
(2)1
| 5 |
| 7 |
| 2 |
| 3 |
=1
| 5 |
| 7 |
=
| 12 |
| 7 |
| 12 |
| 5 |
=
| 5 |
| 7 |
(3)(6-0.558)÷9.07×(0.7-0.075)
=5.442÷9.07×0.625
=0.6×0.625
=0.375;
(4)6.3×[(10
| 1 |
| 3 |
| 1 |
| 2 |
| 5 |
| 6 |
| 4 |
| 5 |
=6.3×(
| 41 |
| 6 |
| 6 |
| 41 |
| 5 |
| 9 |
=6.3×
| 5 |
| 9 |
=3.5;
(5)1
| 1 |
| 2 |
| 1 |
| 4 |
| 2 |
| 3 |
=
| 3 |
| 2 |
| 9 |
| 4 |
| 32 |
| 3 |
=
| 3 |
| 2 |
| 9 |
| 4 |
| 1 |
| 9 |
| 32 |
| 3 |
=4;
(6)[14.8+(3
| 3 |
| 7 |
| 3 |
| 25 |
| 2 |
| 3 |
=(14.8+
| 24 |
| 14 |
| 28 |
| 25 |
| 3 |
| 8 |
=(14.8+1.92)×
| 3 |
| 8 |
=16.72×
| 3 |
| 8 |
=6.27.
点评:在完成脱式计算题目时,要注意计算过程的完整性,中间不要有太大跳跃.
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