题目内容
递等式计算:
(
|
3.6×98+36×0.2 | ||||||||
35÷[(
|
9.57-(2.57+3.38)-2.62. |
分析:(1)(3)依据四则运算顺序,先算第二级运算,再算第一级运算,如果只含有同一级运算,按照从左到右顺序计算,有括号先算括号里面的顺序解答,
(2)运用乘法分配律解答,
(4)运用减法的性质解答.
(2)运用乘法分配律解答,
(4)运用减法的性质解答.
解答:解:(1)(
-
)÷
+
,
=
÷
+
,
=
+
,
=1;
(2)3.6×98+36×0.2,
=3.6×(9.8+0.2),
=3.6×10,
=36;
(3)35÷[(
-
)×3],
=35÷[
×3],
=35÷
,
=70;
(4)9.57-(2.57+3.38)-2.62,
=(9.57-2.57)-(3.38+2.62),
=7-6,
=1.
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 2 |
| 5 |
| 6 |
=
| 1 |
| 12 |
| 1 |
| 2 |
| 5 |
| 6 |
=
| 1 |
| 6 |
| 5 |
| 6 |
=1;
(2)3.6×98+36×0.2,
=3.6×(9.8+0.2),
=3.6×10,
=36;
(3)35÷[(
| 5 |
| 6 |
| 2 |
| 3 |
=35÷[
| 1 |
| 6 |
=35÷
| 1 |
| 2 |
=70;
(4)9.57-(2.57+3.38)-2.62,
=(9.57-2.57)-(3.38+2.62),
=7-6,
=1.
点评:本题考查知识点:(1)正确依据四则运算顺序进行计算,(2)正确运用简便算法解决问题.
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