题目内容
能简算的要简算.
23-
×
÷
-
×
×
+
÷3
5÷[(
+
)×
]
×99+
x=
(解方程)
与
的差是它们和的几分之几?
23-
| 8 |
| 9 |
| 3 |
| 4 |
| 1 |
| 27 |
| 5 |
| 7 |
| 5 |
| 7 |
| 5 |
| 9 |
| 7 |
| 8 |
| 2 |
| 3 |
| 7 |
| 8 |
5÷[(
| 2 |
| 3 |
| 1 |
| 5 |
| 1 |
| 13 |
| 4 |
| 25 |
| 4 |
| 25 |
| 7 |
| 8 |
| 21 |
| 40 |
| 5 |
| 6 |
| 3 |
| 4 |
分析:(1)先算乘除,再算减法;
(2)(5)运用乘法分配律简算;
(3)把除法改为乘法,运用乘法分配律简算;
(4)先算小括号内的,再算中括号内的,最后算括号外的;
(6)根据等式的性质两边同乘
即可;
(7)先求出二者之差与二者之和,然后相除即可.
(2)(5)运用乘法分配律简算;
(3)把除法改为乘法,运用乘法分配律简算;
(4)先算小括号内的,再算中括号内的,最后算括号外的;
(6)根据等式的性质两边同乘
| 8 |
| 7 |
(7)先求出二者之差与二者之和,然后相除即可.
解答:解:(1)23-
×
÷
,
=23-
×
×27,
=23-18,
=5;
(2)
-
×
,
=
×(1-
),
=
×
,
=
;
(3)
×
+
÷3,
=
×
+
×
,
=
×(
+
),
=
×1,
=
;
(4)5÷[(
+
)×
],
=5÷[
×
],
=5÷
,
=75;
(5)
×99+
,
=
×(99+1),
=
×100,
=16;
(6)
x=
,
x×
=
×
,
x=
;
(7)(
-
)÷(
+
),
=
÷
,
=
×
,
=
.
| 8 |
| 9 |
| 3 |
| 4 |
| 1 |
| 27 |
=23-
| 8 |
| 9 |
| 3 |
| 4 |
=23-18,
=5;
(2)
| 5 |
| 7 |
| 5 |
| 7 |
| 5 |
| 9 |
=
| 5 |
| 7 |
| 5 |
| 9 |
=
| 5 |
| 7 |
| 4 |
| 9 |
=
| 20 |
| 63 |
(3)
| 7 |
| 8 |
| 2 |
| 3 |
| 7 |
| 8 |
=
| 7 |
| 8 |
| 2 |
| 3 |
| 7 |
| 8 |
| 1 |
| 3 |
=
| 7 |
| 8 |
| 2 |
| 3 |
| 1 |
| 3 |
=
| 7 |
| 8 |
=
| 7 |
| 8 |
(4)5÷[(
| 2 |
| 3 |
| 1 |
| 5 |
| 1 |
| 13 |
=5÷[
| 13 |
| 15 |
| 1 |
| 13 |
=5÷
| 1 |
| 15 |
=75;
(5)
| 4 |
| 25 |
| 4 |
| 25 |
=
| 4 |
| 25 |
=
| 4 |
| 25 |
=16;
(6)
| 7 |
| 8 |
| 21 |
| 40 |
| 7 |
| 8 |
| 8 |
| 7 |
| 21 |
| 40 |
| 8 |
| 7 |
x=
| 3 |
| 5 |
(7)(
| 5 |
| 6 |
| 3 |
| 4 |
| 5 |
| 6 |
| 3 |
| 4 |
=
| 1 |
| 12 |
| 19 |
| 12 |
=
| 1 |
| 12 |
| 12 |
| 9 |
=
| 1 |
| 9 |
点评:考查了四则混合运算和解方程,注意运算顺序和运算法则,灵活运用所学的运算定律进行简便计算;在解方程时,根据等式的性质.
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