题目内容
(1)(9
+7
)÷(
+
)
(2)(1+
+
+
)×
(3)
-
+
-
+
-
(4)
+
+
+
+
.
| 2 |
| 7 |
| 2 |
| 9 |
| 5 |
| 7 |
| 5 |
| 9 |
(2)(1+
| 1 |
| 3 |
| 2 |
| 5 |
| 1 |
| 6 |
| 5 |
| 3 |
(3)
| 4 |
| 3 |
| 7 |
| 12 |
| 9 |
| 20 |
| 11 |
| 30 |
| 13 |
| 42 |
| 15 |
| 56 |
(4)
| 1 |
| 1×5 |
| 1 |
| 5×9 |
| 1 |
| 9×13 |
| 1 |
| 13×17 |
| 1 |
| 17×21 |
分析:(1)先通分,7和9的最小公因数是63,然后再运用分数的除法的计算法则进行计算.
(2)运用乘法的分配律进行计算,然后通分,按照同分母分数的计算法则进行计算即可.
(3)先通分,再按照同分母分数的加减法的计算法则进行计算即可.
(4)运用
=
-
进行计算,所以原式=(1-
+
-
+
-
+
-
+
-
)÷4,进行计算即可.
(2)运用乘法的分配律进行计算,然后通分,按照同分母分数的计算法则进行计算即可.
(3)先通分,再按照同分母分数的加减法的计算法则进行计算即可.
(4)运用
| 1 |
| n(n+1) |
| 1 |
| n |
| 1 |
| n+1 |
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 9 |
| 1 |
| 9 |
| 1 |
| 13 |
| 1 |
| 13 |
| 1 |
| 17 |
| 1 |
| 17 |
| 1 |
| 21 |
解答:解:(1)(9
+7
)÷(
+
),
=(9
+7
)÷(
+
),
=16
÷
,
=
×
,
=13;
(2)(1+
+
+
)×
,
=
+
+
+
,
=
+
+
+
,
=
,
=3
;
(3)
-
+
-
+
-
,
=
-
+
-
+
-
,
=
+
-
,
=
+
-
,
=
-
=
-
,
=
;
(4)
+
+
+
+
,
=(1-
+
-
+
-
+
-
+
-
)÷4,
=(1-
)×
,
=
×
,
=
.
| 2 |
| 7 |
| 2 |
| 9 |
| 5 |
| 7 |
| 5 |
| 9 |
=(9
| 18 |
| 63 |
| 14 |
| 63 |
| 45 |
| 63 |
| 35 |
| 63 |
=16
| 32 |
| 63 |
| 80 |
| 63 |
=
| 1040 |
| 63 |
| 63 |
| 80 |
=13;
(2)(1+
| 1 |
| 3 |
| 2 |
| 5 |
| 1 |
| 6 |
| 5 |
| 3 |
=
| 5 |
| 3 |
| 5 |
| 9 |
| 2 |
| 3 |
| 5 |
| 18 |
=
| 30 |
| 18 |
| 10 |
| 18 |
| 12 |
| 18 |
| 5 |
| 18 |
=
| 57 |
| 18 |
=3
| 1 |
| 6 |
(3)
| 4 |
| 3 |
| 7 |
| 12 |
| 9 |
| 20 |
| 11 |
| 30 |
| 13 |
| 42 |
| 15 |
| 56 |
=
| 80 |
| 60 |
| 35 |
| 60 |
| 27 |
| 60 |
| 22 |
| 60 |
| 13 |
| 42 |
| 15 |
| 56 |
=
| 5 |
| 6 |
| 13 |
| 42 |
| 15 |
| 56 |
=
| 35 |
| 42 |
| 13 |
| 42 |
| 15 |
| 56 |
=
| 8 |
| 7 |
| 15 |
| 56 |
=
| 64 |
| 56 |
| 15 |
| 56 |
=
| 7 |
| 8 |
(4)
| 1 |
| 1×5 |
| 1 |
| 5×9 |
| 1 |
| 9×13 |
| 1 |
| 13×17 |
| 1 |
| 17×21 |
=(1-
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 9 |
| 1 |
| 9 |
| 1 |
| 13 |
| 1 |
| 13 |
| 1 |
| 17 |
| 1 |
| 17 |
| 1 |
| 21 |
=(1-
| 1 |
| 21 |
| 1 |
| 4 |
=
| 20 |
| 21 |
| 1 |
| 4 |
=
| 5 |
| 21 |
点评:本题考查了学生通过约分对分数四则混合运题目进行简算的能力.
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